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3 years ago

M: -1/2 Point: (-1, 3) Solve for y=mx+b Help

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

Answer:

y= (-1/2)x+(5/2)

Step-by-step explanation:

equation point slope

(y-y1)=m(x-x1)

y-3 = -1/2(x+1) add -3 to both sides and distribute

y=( -x/2) +(-1/2)+3 rewrite 3 as 6/2

y=(-1/2)x +(-1+6/2) solve

y= (-1/2)x+(5/2)

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This table shows the number of points two teams scored in five games

mezya [45]

Answer:

2.16

Step-by-step explanation:

The question is on mean absolute deviation

The general formula ,

Mean deviation = sum║x-μ║/N where x is the each individual value, μ is the mean and N is number of values

Team 1

Finding the mean ;

$mean= \frac{51+47+35+48+64}{5} =49$

Points Absolute Deviation from mean

51 2

47 2

35 14

48 1

64 15

Sum 34

Absolute mean deviation = 34/5= 6.8

Team 2

Finding the mean

$mean=\frac{27+55+53+38+41}{5} = 42.8$

Points Absolute deviation from the mean

27 15.8

55 12.2

53 10.2

38 4.8

41 1.8

Sum 44.8

Absolute deviation from the mean = 44.8/5 =8.96

Solution

Difference in mean absolute deviation of the two teams = 8.96-6.8 = 2.16

5 0

4 years ago

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

Mrs. Humble is filling bags with peanuts to give as gifts. Each bag will contain 1 and 3 over 4 pounds of peanuts. The peanuts c

DerKrebs [107]

Answer:

$8.75

Step-by-step explanation:

STEP TO TAKE TO DETERMINE THE ANSWER

Multiply 13/4 pounds by the cost of one pound of peanut. To do this, convert 13/4 to an improper fraction and then multiply it by $5

$1\frac{3}{4}$ = $\frac{7}{4}$

$\frac{7}{4}$ × 5 = $\frac{35}{4}$ = $8\frac{3}{4}$ = $8.75

5 0

3 years ago

Alessia is paid 1.4 times her normal hourly rate for each hour she works over 30 hours in a week. Last week she worked 35 hours

pantera1 [17]

$x- normal\ hourly\ rate\\\\
35\ hours\ of\ work:\\
30\ normal\ hours\ and\ 5\ overtime\\\\
30x+5*1,4x=436,60\\\\
30x+7x=436,60\\\\
37x=436,60\ \ \ :37\\\\
x=11,8\$\\\\
\textbf{Alessia's\ normal\ hourly\ rate\ in\ work\ is\ 11,8\$.}$

4 0

3 years ago

Read 2 more answers

I NEEED HELP!!!!!! AGAIN

saveliy_v [14]

Answer:

Step-by-step explanation:

You add and divide for the mean so you add all of them together (which is 16) and you divide it by 4 (because there are 4 teams) which gives you the answer 4

6 0

3 years ago