I think you wrote that incorrectly
Answer:
ln(5/3)
Step-by-step explanation:
The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.
<h3>Limit</h3>
We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.
![\diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}](https://tex.z-dn.net/?f=%5Cdiplaystyle%20%5Clim%5Climits_%7Bx%5Cto1%7D%7B%28%5Cln%28x%5E5-1%29-%5Cln%28x%5E3-1%29%29%7D%3D%5Clim%5Climits_%7Bx%5Cto1%7D%5Cln%7B%5Cleft%28%5Cdfrac%7Bx%5E5-1%7D%7Bx%5E3-1%7D%5Cright%29%7D%5C%5C%5C%5C%3D%5Clim%5Climits_%7Bx%5Cto1%7D%5Cln%5Cleft%28%5Cdfrac%7Bx%5E4%2Bx%5E3%2Bx%5E2%2Bx%2B1%7D%7Bx%5E2%2Bx%2B1%7D%5Cright%29%3D%5Cln%7B%5Cdfrac%7B5%7D%7B3%7D%7D)
The graph of y > mx, where m > 0, consists of a dashed line and a shaded half plane. The line has a positive slope and passes through the origin. The shaded half plane is above the line.
Answer:
The answer is B. 581/90
Step-by-step explanation:
just divide 581 by 90 and you'll find that it is equivelent to 6.4<u>5</u>
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Hope that helps!