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kow [346]
3 years ago
12

What is the geometric sequence of -13,117,-1053

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:

-19

Step-by-step explanation:

Use the geometric ratio r=a2/a1

So 117/-13 = -9

-13*-9= 117

117*-9= -1053

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50 POINTS!!!!!!!
stira [4]

Answer:

For this transition of equations, the graph of g(x) will be translated left 2 units with respect to the graph of f(x), so your answer choice will be A.

Step-by-step explanation:

In this equation, g(x) is changed by adding 2 and closing part of the equation in parenthases, this results in the translation 2 units left, which can be proven by a graph and my answer.

3 0
3 years ago
What value represents the horizontal translation from the graph of the parent function f(x) = x2 to the graph of the function
g100num [7]
The -4  represents  a horizontal translation of 4 units to the right
4 0
3 years ago
Read 2 more answers
1. -7-(-2) *
Morgarella [4.7K]
1. -7-(-2)
= -7+2= -5

2. 5-(-3)
= 5+3=8

3. -6-4
= -6+(-4)= -10

4. -3-(-3)
= -3+3= 0
8 0
3 years ago
Nia solved the equation -1.98 = 5.2v + 13.1. Her answer was v = -2.9. She is fairly confident about her answer, but wants to do
d1i1m1o1n [39]
To solve this, just round each number. -1.98≈-2, 5.2≈5, -2.9≈-3, 13.1≈13. The only answer choice which correctly rounds these is A, -2=5(-3)+13
4 0
3 years ago
The whole numbers a and b are divisible by c. Is a+b divisible by c? Is b−a divisible by c? Explain your reasoning.
gizmo_the_mogwai [7]

Answer:

a+b is divisible by c since d and e are also whole numbers.

b-a is divisible by c since d and e are also whole numbers.

Step-by-step explanation:

Let a, b whole number that are divisible by c. Then, we have that d = \frac{a}{c} and e = \frac{b}{c}, which are also whole numbers. We proceed to prove that a + b is divisible by c:

1) d = \frac{a}{c}, e = \frac{b}{c}, a, b , c, d, e \in \mathbb{Z} Given

2) d + e = \frac{a}{c}+\frac{b}{c} Compatibility with addition

3) d+e = a\cdot c^{-1}+b\cdot c^{-1} Definition of division

4) d + e = c^{-1}\cdot (a+b) Commutative and distributive properties

5) d+e = (a+b) \cdot c^{-1} Commutative properties

6) d+e = \frac{a+b}{c} Definition of division/Result

Therefore, a+b is divisible by c since d and e are also whole numbers.

We proceed to prove that b-a is divisible by c:

1) d = \frac{a}{c}, e = \frac{b}{c}, a, b , c, d, e \in \mathbb{Z} Given

2) d\cdot (-1) = \frac{a}{c}\cdot (-1) Compatibility with multiplication

3) e + d\cdot (-1) = \frac{b}{c}+\frac{a}{c}\cdot (-1) Compatibility with addition

4) e + d\cdot (-1) = b\cdot c^{-1}+(a\cdot c^{-1})\cdot (-1) Definition of division

5) e + d\cdot (-1) = b\cdot c^{-1} + [a\cdot (-1)]\cdot c^{-1} Associative and commutative properties

6) e + d\cdot (-1) = c^{-1}\cdot [b+a\cdot (-1)] Commutative and distributive properties.

7) e+d\cdot (-1) = [b+a\cdot (-1)]\cdot c^{-1} Commutative properties.

8) e + d\cdot (-1) = \frac{b+a\cdot (-1)}{c} Definition of division

9) e-d = \frac{b-a}{c} (-1)\cdot a = -a/Definition of subtraction

Therefore, b-a is divisible by c since d and e are also whole numbers.

7 0
3 years ago
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