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galina1969 [7]
3 years ago
7

6. Primary succession usually occurs after which catastrophic events?

Chemistry
1 answer:
stealth61 [152]3 years ago
7 0

Answer: d. Glaciers moving revealing bare rock underneath

Explanation:

Primary succession is what happens when living things colonise an area that was previously uncolonized because it had been destroyed or hadn't been created yet.

When glaciers move on from areas and expose the bare rock underneath, these areas are new and so primary succession will take place as living things begin to colonize this new area.

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Which of these items best describes the arrangement of electrons in an atom of sulfur? A. Eight electrons in its first energy le
Serga [27]

D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level.

Please correct me if I'm wrong!! :)


6 0
3 years ago
Read 2 more answers
What is the limiting reactant in a reaction where 10.0 mol of iron is treated with 12.0 mol of bromine? The product that forms i
hammer [34]

<u>Answer:</u> The limiting reagent in the reaction is bromine.

<u>Explanation:</u>

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

Given values:

Moles of iron = 10.0 moles

Moles of bromine = 12.0 moles

The chemical equation for the reaction of iron and bromine follows:

2Fe+3Br_2\rightarrow 2FeBr_3

By the stoichiometry of the reaction:

If 3 moles of bromine reacts with 2 moles of iron

So, 12.0 moles of bromine will react with = \frac{2}{3}\times 12.0=8moles of iron

As the given amount of iron is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Hence, bromine is considered a limiting reagent because it limits the formation of the product.

Thus, the limiting reagent in the reaction is bromine.

3 0
3 years ago
A solution is prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume
MissTica

Answer:

4.56 X 10^ -4 g/mL

Explanation:

A solution is  prepared by diluting 6.0 mL of a 7.6 x 10-4 g/mL solution to a total volume of 10.0 mL. Calculate the concentration of the dilute solution.

(7.6 X10^-4  gm/m L) x( 6.0 m L ) = 45.6 X 10^-4 g

this is dissolved )in 10 m L=45.6 X 10^-4  g/ 10

4.56 X 10^ -4 g/mL

check

6/10 =0.6

4.56/7.6 = o.,6

4 0
3 years ago
g Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equ
ipn [44]

Answer:

0.719M AgNO₃

Explanation:

Based on the reaction:

MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂

<em>1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃</em>

<em />

To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:

<em>Moles AgNO₃:</em>

<em />

Moles of MgBr₂ are:

50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.

As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:

0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =

0.0100 moles of AgNO₃ are in the solution.

And molarity is:

0.0100 moles AgNO₃ / 0.0139L =

<h3>0.719M AgNO₃</h3>
3 0
3 years ago
Laws differ from theories because laws do not provide
o-na [289]

Answer:

C. An explanation

7 0
3 years ago
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