Answer:
calcium to give calcium oxide to give calcium trioxocabonate (limestone) to give carbondioxide
Answer:
Relative volume of ether to water that should be used for the extraction = 1.205
Explanation:
The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).
K = (C₁/C₂)
Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).
If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.
Let the volume of ether required be x mL.
Let the volume of water required be y mL.
Relative volume of ether to water that should be used for the extraction = (x/y)
Mass concentration of the organic substance X in ether = (0.94/x)
Mass concentration of organic substance X in water = (0.06/y)
The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.
13 = (0.94/x) ÷ (0.06/y)
13 = (0.94/x) × (y/0.06)
13 = (15.667y/x)
(x/y) = (15.667/13) = 1.205
Hope this Helps!!!
Answer:
-43.3 °C
Explanation:
To find the temperature, you need to use the Ideal Gas Law equation. The equation looks like this:
PV = nRT
In this formula,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Law constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
By plugging the given values into the equation and simplifying, you can find the temperature. After you get a temperature, you need to convert it into Celsius.
P = 2.88 atm R = 0.08206 atm*L/mol*K
V = 3.76 L T = ? K
n = 0.574 moles
PV = nRT
(2.88 atm)(3.76 L) = (0.574 moles)(0.08206 atm*L/mol*K)T
10.8288 = (0.04710244)T
230. K = T
Kelvin - 273.15 = Celsius
230 K - 273.15 = -43.3 °C
Answer:
The fourth one down
Explanation:
It is the only setup in which the units of "cm" and "in" cancel correctly and give the desired units of "ft."
The second one down has the correct units but the wrong conversion factor for converting centimetres to inches.
