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Nikolay [14]
3 years ago
10

What chemical property is given to a biomolecule with a hydroxyl (--oh) functional group?

Chemistry
1 answer:
marin [14]3 years ago
3 0

A biomolecule with a hydroxyl (--oh) functional group is given the polar chemical property since organic molecules with an OH group are polar.

 

A part of a larger molecule is made up by a functional group. The hydroxyl group (-OH) that characterizes alcohols, an oxygen with a hydrogen attached, is an example of it. This group can be found on any number of different molecules.

 

Functional groups have characteristic chemistries, just as elements have unique properties., although perhaps not identically, to an -OH on another molecule. Although perhaps not identically to an -OH on another molecule, an -OH group on one molecule will tend to react similarly.

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Complete the equation for the dissociation of Fe(ClO4)3(aq). Omit water from the equations because it is understood to be presen
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Answer:

The equation that tends to answer this question, (omitting the presence of water) is:

Fe (ClO4) 3 -----------> Fe (+3) + ClO4 (-1)

Explanation:

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Which equation represents sublimation?
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According to the given choices only third one is correct because solid H</span><span>₂<span>O goes to its vapor without going liquid state. </span></span>

8 0
3 years ago
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Which of the following is the correct definition of chemical energy?
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A

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5 0
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At 25 ∘ C , the equilibrium partial pressures for the reaction 3 A ( g ) + 4 B ( g ) − ⇀ ↽ − 2 C ( g ) + 3 D ( g ) were found to
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<u>Answer:</u> The standard Gibbs free energy of the given reaction is 6.84 kJ

<u>Explanation:</u>

For the given chemical equation:

3A(g)+4B(g)\rightleftharpoons 2C(g)+3D(g)

The expression of K_p for above equation follows:

K_p=\frac{(p_C)^2\times (p_D)^3}{(p_A)^3\times (p_B)^4}

We are given:

(p_A)_{eq}=5.70atm\\(p_B)_{eq}=4.00atm\\(p_C)_{eq}=4.22atm\\(p_D)_{eq}=5.52atm

Putting values in above expression, we get:

K_p=\frac{(4.22)^2\times (5.52)^3}{(5.70)^3\times (4.00)^4}\\\\K_p=0.0632

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = Gas constant = 8.314 J/K mol

T = temperature = 25^oC=[273+25]K=298K

K_{eq} = equilibrium constant at 25°C = 0.0632

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (0.0632)\\\\\Delta G^o=6841.7J=6.84kJ

Hence, the standard Gibbs free energy of the given reaction is 6.84 kJ

6 0
4 years ago
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