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goblinko [34]
3 years ago
15

The energy of moving electrons is known as?

Chemistry
1 answer:
andrew-mc [135]3 years ago
3 0
The answer is electrical energy
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The solution you identified in question (1) acts as a buffer due to reactions that occur within the solution when an acid or a b
weeeeeb [17]

Answer:

The answer is "\bold{CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)}"

Explanation:

When HCI is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:

CH_3COONa\ (aq) + HCl\ (aq)\longrightarrow CH_3COOH\ (aq) + NaCl\ (aq)\\\\

 In this, the CH_3COOH is a weak acid so, it not completely dissociated.

CH_3COONa \ (aq) \ \ and \ NaCl were strong electrolytes they are completely dissociated.

The HCl is a strong acid so, it is completely dissociated So, the net ionic equation is:

CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)

8 0
3 years ago
In a exothermic reaction, is heat transfered to or from the surrounding
Monica [59]
In an exothermic reaction, heat is transferred to the surrounding.

Hope this helps, have a great day ahead!
7 0
3 years ago
Read 2 more answers
WHAT IS THE PERCENT BY VOLUME OF ETHANOL IN A SOLUTION THAT CONTAINS 35 mL ETHANOL IN 115 mL OF WATER?
Dmitry [639]
We need to first add both of the solution volumes together 35+115=150. Now we can divide the volume of the ethanol by the total volume 35/150=.233. To double check we can multiply the total volume by the percentage of ethanol by volume we got as a solution 150x.233=35. So the percentage by volume of ethanol in the solution is .233x100=23.3%.
3 0
3 years ago
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg+2 ions?
Mnenie [13.5K]
<span>The number of moles of Cl- ions needed to combine completely with 0.25 mole of Mg+2 ions is:
0.50.</span>
4 0
3 years ago
Calculate the work (kJ) done during a reaction in which the internal volume expands from 20 L to 43 L against an outside pressur
Alenkinab [10]

Answer:

\large \boxed{\text{-10.0 kJ}}

Explanation:

1. Calculate the work

w = - pΔV = -4.3 atm × (43 L - 20 L) = -4.3 × 23 L·atm = -98.9 L·atm

2. Convert litre-atmospheres to joules

w = \text{-98.9 L\cdot$atm } \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm }} = \text{-10000 J} = \textbf{-10.0 kJ}\\\\\text{The work done is $\large \boxed{\textbf{-10.0 kJ}}$}

The negative sign indicates that the work was done against the surroundings.

4 0
3 years ago
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