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Maksim231197 [3]
3 years ago
7

A concentration cell consists of two Sn/Sn2+ half-cells. The solution in one half-cell A is 0.13 M Sn(NO3)2 and is 0.87 M Sn(NO3

)2 in the other half-cell B. Calculate the cell potential at 25 degrees C.
Chemistry
1 answer:
alina1380 [7]3 years ago
6 0
Base on your question where a concentration cell consist of two SN/SN2+half cells. The solution in one half cell A is 0.13M SN(NO3)2 and is 0.87 M Sn(NO3)2 in the other half cell to get the cell potential at 25 degree the answer is 0.059/2 log0.13/0.87
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