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3 years ago

Please help! The problem is in the picture

Mathematics

1 answer:

arlik [135]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope this helps if im wrong im dum:-:

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Help pleaseeeeeeeeeeeee

eduard

Step-by-step explanation:

17.0 there you go I hope this helped

4 0

3 years ago

Read 2 more answers

Please help me on this ratio question I'm stuck

Pavlova-9 [17]

24/6=4
(6x4)+(2x4)+(3x4)=
24+8+12=44=answer!

5 0

3 years ago

Plz help me out again thanks!!

Leya [2.2K]

Answer:

303.2 cubic inches

Step-by-step explanation:

20.6in × 3.8in ×2.9in + 3.7in × 7.1in × 2.9in

= answer

5 0

3 years ago

Read 2 more answers

Alexis is knitting a blanket 2 meters long. Every 2 decimeters, she changes the color of the yarn to make stripes. How many stri

IgorC [24]

Answer:

There are 10 stripes in the blanket.

Step-by-step explanation:

We are given the following in the question:

Length of blanket = 2 meters

1 meter = 10 decimeter

Length of blanket in decimeter =

$2\times 10 = 20\text{ decimeters}$

Change of color = Every 2 decimeters.

Number of stripe =

$=\dfrac{\text{Length of blanket}}{\text{Length of change of color of stripe}}\\\\=\dfrac{20}{2} = 10$

Thus, there are 10 stripes in the blanket.

3 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

3 years ago