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irina [24]
2 years ago
12

A train is traveling at a constant speed and goes a distance of 7 ½ kilometers in 6 minutes. The train will continue to travel a

t this speed. The train will travel a distance of d kilometers in m minutes. Write an equation that represents the relationship between d and m.
Mathematics
1 answer:
g100num [7]2 years ago
6 0

Answer:

m = 1.25d

Step-by-step explanation:

A train is traveling at a constant speed and goes a distance of 7 ½ kilometers or 7.5 km in 6 minutes.

6 min = 7.5 km

1 min = (7.5/6) km/min

= 1.25 km/min

or

In m min, (7.5/6)d is travelled by the train. Hence, the relation between d and  is :

m=\dfrac{7.5d}{6}\\\\m = 1.25d

Hence, this is the required solution.

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son4ous [18]

Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

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2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

w₁=\sqrt{13}(Cos(\frac{0.4426}{2}) + i Sin(\frac{0.4426}{2}))= 2- 3i

w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

5) z = 21 − 20i  ⇒ r=29 θ= -0.8098 rad

w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

6) z = 16 − 30i ⇒ r=34 θ= -1.0808 rad

w₁=\sqrt{34}(Cos(\frac{-1.0808}{2}) + i Sin(\frac{-1.0808}{2}))= 5 - 3i

w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
3 years ago
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levacccp [35]

Answer:

9 groups

Step-by-step explanation:

6 0
3 years ago
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beks73 [17]

Given:

The location of point S on a coordinate plane.

To find:

The ordered pair for the point S.

Solution:

A point is defined as (x,y), where, |x| is the distance between the point and y-axis, and |y| be the distance between the point and x-axis. Signs of coordinates depend on the quadrant.

From the given graph it is clear that,

Distance between S and y-axis = 3.5

Distance between S and x-axis = 5.5

Point S lies in 3rd quadrant, it means x- and y-coordinates are negative.

Therefore, the ordered pair of point S is (-3.5,-5.5).

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A red blood cell is 0.000007 m in diameter. There are about 20,000,000,000,000 red blood cells in a 125 lb person. if all the re
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ikadub [295]

Answer:

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I hope this helps

7 0
2 years ago
Read 2 more answers
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