<em>A cylinder of argon gas contains 50.0 L of Ar at 18.4 atm and 127 °C. How many moles of argon are in the cylinder?</em>
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Number moles of Argon : 28.03
<h3>Further explanation</h3>Given
The volume of gas=50 L
P = 18.4 atm
T = 127+273=400 K
Required
moles of Argon
Solution
Use ideal gas Law :
The value of ΔS° for reaction is - 22.2 J/K.mol
→
Calculation,
Given value of S°(J/K.mol) for
= 248.5
= 240.5
= 210.6
= 256.2
Formula used:
ΔS° (Reaction) = ∑S°(Product) - ∑S°(Reactant)
ΔS° = (256.2 + 210.6 ) - ( 248.5 + 240.5) = 466.8 - 489 = - 22.2 J/K.mol
The change in stander entropy of reaction is - 22.2 J/K.mol. The negative sign indicates the that entropy of reaction is decreases when reactant converted into product.
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