I think the correct answer would be the second option. The volume of 1 mol of gas at standard temperature and pressure would be the same for any gas. If and only if the gas is an ideal gas. This is according to the ideal gas law ( PV = nRT ), at STP ( P = 1 atm T = 273.15 K ) you would calculate the volume of the gas to be 22.4 L. So, 1 mol of any ideal gas would occupy 22.4 L of volume. We calculate as follows:
PV = nRT
V = nRT / P
V = (1 mol ) (0.08205 L-atm / mol K) (273.15 K ) / 1 atm
V = 22.4 L <span />
Answer:
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
Explanation:
The Bold Numbers are what you should put. This is balanced
Answer:
float
Explanation:
density= mass/ volume (kg/m^3)
1.59 kg/0.197 m^3
=8.07 kg/m^3
density of H2O= 1000 kg/m3
since density(block)<density(H2O), the block will float
(can also be done in g/cm^3)
1590 g/ (1.97*10^5 cm3)= 0.00807 g/cm^3 < 1 g/cm^3 (h2O)
The potassium chloride is KCl. The gram formula mass of KCl is 39+35.5=74.5 g/mol which means 74.5 g per mole of KCl. So the mass of KCl is 6.90*74.5=514 g.