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3 years ago

( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7)

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

Answer:

Adding ( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7) will equal to

−7ya'+xy+5r2y−5cy−3x−5

LenaWriter [7]3 years ago

6 0

Answer:

heres what you need to do

Step-by-step explanation:

$1.(-7a'y+xy+3x+2)+(5r^{2}y-5cy-6x-7)\\$

combine like terms

$(-7a*2y+4x+2)=(5r^{2}*2y-5c-7)$

now combine from both sides

$(-7a*4y-2x+5r^2-5)$

this is what i got srry in advanced if i was wrong

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Answer:

Six numbers have perfect square factors

Step-by-step explanation:

The numbers with perfect square factors are those numbers that have perfect squares as one of the numbers that can divide them.

They include:

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Answer:

Confidence interval: (30.1,36.9)

Step-by-step explanation:

We are given the following data set:

35.3,30.5,37.4,26.5,13.0,49.9,28.8,44.0,61.6,0.5,40.5,34.9,47.9,36.6,24.1,39.8,47.8,18.5,36.6,39.2,14.5,37.3,40.5,49.3,45.5,28.3,19.5,5.6,52.6,41.4,45.3,39.0,33.7,29.4,14.5,40.1,33.7,36.9,5.6,33.7

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{1339.9}{40} = 33.5$

$S.D = 11$ (given)

n = 40

Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$33.5 \pm 1.96(\frac{11}{\sqrt{40}} ) = 6.34 \pm 3.4 = (30.1,36.9)$

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Step-by-step explanation:

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