Question

( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7)

Answer 1

Answer:

Adding ( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7) will equal to

−7ya'+xy+5r2y−5cy−3x−5

Answer 2

Answer:

heres what you need to do

Step-by-step explanation:

$1.(-7a'y+xy+3x+2)+(5r^{2}y-5cy-6x-7)$

combine like terms

$(-7a*2y+4x+2)=(5r^{2}*2y-5c-7)$

now combine from both sides

$(-7a*4y-2x+5r^2-5)$

this is what i got srry in advanced if i was wrong