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Aleksandr-060686 [28]
3 years ago
7

( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7)

Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

Adding ( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7) will equal to

−7ya'+xy+5r2y−5cy−3x−5

LenaWriter [7]3 years ago
6 0

Answer:

heres what you need to do

Step-by-step explanation:

1.(-7a'y+xy+3x+2)+(5r^{2}y-5cy-6x-7)\\

combine like terms

(-7a*2y+4x+2)=(5r^{2}*2y-5c-7)

now combine from both sides

(-7a*4y-2x+5r^2-5)

this is what i got srry in advanced if i was wrong

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EastWind [94]

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Answer:

  a. 1.48 seconds

Step-by-step explanation:

You want to find the larger value of t such that h(t) = 10.

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  16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form

Using the quadratic formula, we find the values of t to be ...

  t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32

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The ball goes in the hoop about 1.48 seconds after it is thrown.

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<em>Additional comment</em>

The quadratic formula tells us the solution to ...

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3 years ago
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Sunny_sXe [5.5K]

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Answer

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Answer:

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