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Aleksandr-060686 [28]
3 years ago
7

( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7)

Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

Adding ( - 7a'y + xy + 3x + 2) + (5r²y – 5cy - 6x – 7) will equal to

−7ya'+xy+5r2y−5cy−3x−5

LenaWriter [7]3 years ago
6 0

Answer:

heres what you need to do

Step-by-step explanation:

1.(-7a'y+xy+3x+2)+(5r^{2}y-5cy-6x-7)\\

combine like terms

(-7a*2y+4x+2)=(5r^{2}*2y-5c-7)

now combine from both sides

(-7a*4y-2x+5r^2-5)

this is what i got srry in advanced if i was wrong

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<h3>Which statements are true of the graph of the function?</h3>

The function, 4x - 15 shows that 15 is the y-intercept which means that the graph will cross the y-axis at (0,15).

The point of discontinuity is x = - 2 and we see this with the gap created at x < -2 and -2 ≤ x ≤ 4.

The graph is indeed increasing over the interval (4, ∞o) because any value of x that is greater than 4 will increase f(x) = 3^x^-^4.

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2 years ago
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Step-by-step explanation:

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