Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Answer:
The law says the sum of all forms of energy is constant :)
Answer:
When water droplets get too heavy.
Explanation:
Hope this helps.
Answer:
∆H = negative and ∆S = positive.
Explanation:
The reaction given in the question is spontaneous at room temperature ,
hence ,
The the gibbs free energy , i.e. ,∆G will be negative for spontaneous reaction
According to the formula ,
∆G = ∆H -T∆S
The value of ∆G can be negative , if ∆H has a negative value and ∆S has a positive value , because , T∆S , has a negative sign .
Hence , the answer will be , ∆H = negative and ∆S = positive.
