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4 years ago

What is the mass of sodium (Na) in 50 grams of table salt (NaCl)? Show your work.

Chemistry

2 answers:

Margaret [11]4 years ago

8 0

Answer:

19 g

Explanation:

Data Given:

Sodium Chloride (table salt) = 50 g

Amount of sodium (Na) = ?

Solution:

Molecular weight calculation:

NaCl = 23 + 35.5

NaCl = 58.5 g/mol

Mass contributed by Sodium = 23 g

calculate the mole percent composition of sodium (Na) in sodium Chloride.

Since the percentage of compound is 100

So,

Percent of sodium (Na) = 23 / 58.5 x 100

Percent of sodium (Na) = 39.3 %

It means that for ever gram of sodium chloride there is 0.393 g of Na is present.

So,

for the 50 grams of table salt (NaCl) the mass of Na will be

mass of sodium (Na) = 0.393 x 50 g

mass of sodium (Na) = 19 g

Arturiano [62]4 years ago

3 0

Answer:

1.20 on Plato

Explanation:

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3 years ago

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3 years ago

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3 years ago

At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare

OleMash [197]

Answer:

$P_{CCl_4}=52.43torr$

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

$P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}$

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

$x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576$

Therefore, the partial pressure of chloroform turns out to be:

$P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr$

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3 years ago