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Papessa [141]
2 years ago
10

Collision Lab

Physics
2 answers:
saul85 [17]2 years ago
8 0

Answer:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

Explanation:

Sholpan [36]2 years ago
3 0

Answer:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

Explanation:

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Do the same thing you were doing
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I would say that B seems more accurate because rhythm and tone seems like a poem
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Copernicus's model of the universe differs from Ptolemy's because Copernicus believed
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That the Sun was the center of the universe.

Explanation:

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Part a of the drawing shows a bucket of water suspended from the pulley of a well; the tension in the rope is 90.5 n. part b sho
Butoxors [25]
Missing figure in the problem: https://www.physicsforums.com/attachments/p4-46-gif.117834/

Solution:

part a) The bucket is not moving so the resultant of the forces acting on it is zero. Let's apply the equation of equilibrium. We have:
mg-2T=0
so
mg=2T
where T=90.5 N is the tension of the rope, and a factor 2 is applied because the string holds the bucket twice. From this we find
mg=2\cdot 90.5 N= 181 N

part b) Here the situation is different: the string holds the bucket only in one point. Moreover, the bucket is pulled up at constant velocity, so zero acceleration: this means that the resultant of the forces acting on the bucket is zero. Therefore, the equation of equilibrium in this case is
mg-T=0
and so, since we know from part a) that mg=181 N, we can find the new tension T:
T=mg=181 N


3 0
3 years ago
A sample of gold has a mass of 38.6 grams and a volume of 2 cm3. What is the density of gold
Natali5045456 [20]

Answer:

19.3 g/cm^3

Explanation:

The density of a material is given by

\rho = \frac{m}{V}

where

m is the mass of the sample

V is its volume

for the sample of gold in this problem,

m = 38.6 g

V=2 cm^3

Substituting into the formula, we find the density of gold:

\rho = \frac{38.6}{2}=19.3 g/cm^3

5 0
3 years ago
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