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Tju [1.3M]
3 years ago
12

Which of the following statements is accurate

Physics
2 answers:
natta225 [31]3 years ago
8 0
I would say that B seems more accurate because rhythm and tone seems like a poem
CaHeK987 [17]3 years ago
5 0
D. i believe not 100% sure. 
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The Astronomer Carl Sagan is famous. Why?
Zolol [24]
Mainly because he was Johnny Carson's advisor and consultant
on space, astronomy, and science in general, and he appeared
on The Tonight Show Starring Johnny Carson many times.
6 0
3 years ago
While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving
Natali [406]

Answer:21.33^{\circ}

Explanation:

Given

velocity of driver v_1=25 m/s w.r.t ground towards north

driver observes that rain is making an angle of 38^{\circ} with vertical

While returning v_2=25 m/s w.r.t. ground towards south

suppose u_1=velocity of rain drop relative car while car is going towards north

u_2=velocity of rain drop relative car while car is going towards south

z=vector sum of u_1 & v_1

Now from graph

\tan 38=\frac{v_1+v_2}{u_2}

u_2=\frac{25+25}{\tan 38}=64 m/s

z=\vec{u_2}+\vec{v_2}

therefore magnitude of z is given by

|z|=\sqrt{u_2^2+v_2^2}

|z|=\sqrt{64^2+25^2}

|z|=68.70 m/s

\tan A=\frac{v_2}{u_2}

\tan A=\frac{25}{64}=0.3906

A=21.33^{\circ}

Thus rain drops make an angle of 21.33^{\circ} w.r.t to ground

6 0
2 years ago
A projectile is launched with a horizontal velocity of 20 m/s and an initial vertical velocity of 20 m/s. What is the projectile
cestrela7 [59]

Answer:

Vertical acceleration 9.8 m/s² downward

Horizontal acceleration 0.0 m/s²

assuming no air resistance.

6 0
2 years ago
The engine starter and a headlight of a car are connected in parallel to the 12.0-V car battery. In this situation, the headligh
stepladder [879]

Answer:

The total power they will consume in series is approximately 2.257 W

Explanation:

The connection arrangement of the headlight and the engine starter = Parallel to the battery

The voltage of the battery, V = 12.0 V

The power at which the headlight operates in parallel, P_{headlight} = 38 W

The power at which the kick starter operates in parallel, P_{kick \ starter} = 2.40 kW

We have;

P = V²/R

Where;

R = The resistance

V = The voltage = 12 V (The voltage is the same in parallel circuit)

For the headlight, we have;

R₁ = V²/P_{headlight}  = 12²/38 = 72/19

R₁ = 72/19 Ω

For the kick starter, we have;

R₂ = V²/P_{kick \ starter} = 12²/2.4 = 60

R₂ = 60 Ω

When the headlight and kick starter are rewired to be in series, we have;

Total resistance, R = R₁ + R₂

Therefore;

R = ((72/19) + 60) Ω = (1212/19) Ω

The current flowing, I = V/R

∴ I = 12 V/(1212/19) Ω = (19/101) A

We note that power, P = I²R

In the series connection, we have;

P_{headlight} = I² × R₁

∴ P_{headlight} = ((19/101) A)² × 72/19 Ω = 1368/10201 W ≈ 0.134 W

The power at which the headlight operates in series, P_{headlight, S} ≈ 0.134 W

P_{kick \ starter} = ((19/101) A)² × 60 Ω = 21660/10201 W ≈ 2.123 W

The power at which the kick starter operates in series, P_{kick \ starter, S} ≈ 2.123 W

The total power they will consume, P_{Total} = P_{headlight, S} + P_{kick \ starter, S}

Therefore;

P_{Total} ≈ 0.134 W + 2.123 W = 2.257 W

4 0
3 years ago
Use the "Law of Reflection" to describe why you cannot see your reflection in a piece<br> of paper.
Anni [7]

Answer:

it does not mirror the image

5 0
3 years ago
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