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Drupady [299]
3 years ago
15

A sample of gold has a mass of 38.6 grams and a volume of 2 cm3. What is the density of gold

Physics
1 answer:
Natali5045456 [20]3 years ago
5 0

Answer:

19.3 g/cm^3

Explanation:

The density of a material is given by

\rho = \frac{m}{V}

where

m is the mass of the sample

V is its volume

for the sample of gold in this problem,

m = 38.6 g

V=2 cm^3

Substituting into the formula, we find the density of gold:

\rho = \frac{38.6}{2}=19.3 g/cm^3

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Most geologists accept radiometric dating techniques as valid because radioactive elements decay at a constant and measurable rate.

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The parent atoms and daughter atoms are compared while studying, and hence age can be calculated easily. Radioactive decay depends upon the given half-life of the atom, which is a constant and is known. So, it would be very easy to calculate the number of progeny atoms and parent atoms and find out their age.

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Answer

given,

mass of the rod = 1.50 Kg

length of rod = 0.85 m

rotational velocity = 5060 rev/min

now calculating the rotational inertia of the system.

I = m L^2        

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Are any rocks that form from another rock as a result of change in blank or blank
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A simple pendulum bhas a period of 3.45s when the length of the pendulum is shortened by 1m the period is 2.81s caculate the ori
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3 years ago
An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period o
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Answer:

Spring constant, k = 24.1 N/m

Explanation:

Given that,

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Time period of oscillation of simple harmonic motion, T = 0.64 s

To find,

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Solution,

In case of simple harmonic motion, the time period of oscillation is given by :

T=2\pi\sqrt{\dfrac{m}{k}}

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