Numerator
<span><span>cos<span>(<span>π/2</span>−x)</span></span>=<span>cos<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>sin<span>(<span>π/2</span>)</span></span><span>sinx</span></span>
now <span><span>cos<span>(<span>π/2</span>)</span></span>=0 and <span>sin<span>(<span>π/2</span>)</span></span>=1</span>
simplifies to : 0 + sinx = sinx
Denominator
<span><span>sin<span>(<span>π/2</span>−x)</span></span>=<span>sin<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>cos<span>(<span>π/2</span>)</span></span><span>sinx</span></span>
simplifies to : cosx + 0 = cosx
<span>⇒<span><span>cos<span>(<span>π/2</span>−x)</span></span><span>sin<span>(<span>π/2</span>−x)</span></span></span>=<span><span>sinx/</span><span>cosx</span></span>=<span>tan<span>x</span></span></span>
I don’t know the first part but i think the second part would be 4^11
Answer:
BC = 23
Step-by-step explanation:
Since ∠ A = ∠ C then the triangle is isosceles with AB = BC, that is
3x + 14 = x + 20 ( subtract x from both sides )
2x + 14 = 20 ( subtract 14 from both sides )
2x = 6 ( divide both sides by 2 )
x = 3
Thus
BC = 3x + 14 = 3(3) + 14 = 9 + 14 = 23
Answer:Division! :)
Step-by-step explanation:
Answer:
hi
Step-by-step explanation:hi
