Answer:
Amount of air left in the cylinder=m
=0.357 Kg
The amount of heat transfer=Q=0
Explanation:
Given
Initial pressure=P1=300 KPa
Initial volume=V1=0.2
Initial temperature=T
=20 C
Final Volume=
=0.1
Using gas equation
m1==(300*0.2)/(.287*293)
m1=0.714 Kg
Similarly
m2=(P2*V2)/R*T2
m2=(300*0.1)/(0.287*293)
m2=0.357 Kg
Now calculate mass of air left,where me is the mass of air left.
me=m2-m1
me=0.715-0.357
mass of air left=me=0.357 Kg
To find heat transfer we need to apply energy balance equation.
Where me=m1-m2
And as the temperature remains constant,hence the enthalpy also remains constant.
h1=h2=he=h
Q=(me-(m1-m2))*h
me=m1-me
Thus heat transfer=Q=0
so people dont die whaddya think?
Answer:
Below is the desired C++ program for the problem. Do feel free to edit it according to your preference
Explanation:
#include <iostream>
#include <vector>
using namespace std;
void ExactChange(int userTotal, vector<int> &coinVals) {
coinVals.reserve(5);
coinVals[0] = userTotal / 100;
userTotal %= 100;
coinVals[1] = userTotal / 25;
userTotal %= 25;
coinVals[2] = userTotal / 10;
userTotal %= 10;
coinVals[3] = userTotal / 5;
userTotal %= 5;
coinVals[4] = userTotal;
}
int main() {
vector<int> coins;
int value;
cin >> value;
if (value <= 0) {
cout << "no change" << endl;
} else {
ExactChange(value, coins);
if (coins[0] != 0) cout << coins[0] << " " << (coins[0] == 1 ? "dollar" : "dollars") << endl;
if (coins[1] != 0) cout << coins[1] << " " << (coins[1] == 1 ? "quarter" : "quarters") << endl;
if (coins[2] != 0) cout << coins[2] << " " << (coins[2] == 1 ? "dime" : "dimes") << endl;
if (coins[3] != 0) cout << coins[3] << " " << (coins[3] == 1 ? "nickel" : "nickels") << endl;
if (coins[4] != 0) cout << coins[4] << " " << (coins[4] == 1 ? "penny" : "pennies") << endl;
}
return 0;
}
Answer:
omg it would burn our insides. we're not made of metal lols
Explanation:
you should mark me as brainliest :)
