Answer:
Correct option is A - O(x)
Explanation:
Given f(x) = 10 and g(x) = x
Hence f(x) is O g(x)
As such correct answer is O(x) which is option A
Answer: I don't agree with the colleague. Because the lab technician may be conducting the shear strength experiment properly.
The difference between the shear strength of the sample in the lab and the field may be due to all or any of the following:
1) Sample size.
2) Sample shape.
3) Sample proportion.
4) Multiple test run on the same sample.
Explanation:
1) The sample size is very important in determining the shear strength of a sample, because the cohesion of a sample will vary with respect to the size of the sample, if the proportion remains the same. Therefore the sample size used in the lab and the field may not be equal.
2) The sample shape tells the arrangements of the particle lattice in the sample, which determines how cohesive a sample can be. Therefore if the shape of the samples are different, the stress properties won't be the same.
3) The cohesion of the sample will increase as the proportion of the sample increases. Therefore if the sample proportion are not the same, then the stress properties of the Mohr circle won't be the same.
4) If at all exactly the same sample used in the lab was the one used in the field, this will reduce the shear strength of the sample, because a repeative experiment on shear strength of a sample will reduce the cohesion of the sample. Therefore the cohesion of the sample during the lab experiment will be more than the cohesion of the sample during the field experiment.
Explanation:
White Board Activity: Practice: A sound has a frequency of 800 Hz. What is the period of the wave? The wave repeats 800 times in 1 second and the period of the function is 1/800 or 0.00125.
Answer is your company’s address
Answer:
a)
b)
Explanation:
a)
In order to solve this problem, we need to start by remembering how the acceleration is related to the velocity of a particle. We have the following relation:
in other words, the acceleration is defined to be the derivative of the velocity function with respect to time. So let's take our speed function:
u=20-2x
if we take its derivative we get:
du=-2dx
this is the same as writting:
we also know that velocity is defined to be:
so we get that:
a=-2u
when substituting we get that:
a=-2(20-2x)
when expanding we get:
a=-40+4x
and now we can use this equation to find our acceleration at x=3, so:
a=-40+4(3)
a=-40+12
b)
the same applies to this problem with the difference that this will be the rate of change of the temperature per m. So we proceed and take the derivative of the temperature function:
T=200-5x
so the rate of change is