Answer:
True Strain at failure = 1.386
Explanation:
For the question, ductility is given in reduction In the area to be 0.75
Let the initial Cross sectional Area of wire be Ao
And the final cross sectional Area of wire of cross sectional Area of wire at fracture be A
(Ao - A)/Ao = ductility = 0.75
Ao - A = 0.75Ao
A = Ao - 0.75Ao
A = 0.25 Ao
True Strain = In (Lf/Lo)
To obtain the ratio of the lengths of wire,
The volume of the wire stays constant, that is, Vo = Vf; Vo = Ao × Lo and Vf = A × Lf
AoLo = ALf
Lf/Lo = Ao/A
In (Lf/Lo) = In (Ao/A) = In (Ao/0.25Ao) = In 4 = 1.386
True Strain = 1.386
Answer:
I would say an Oblique drawing.
Explanation:
An oblique drawing uses 45 degree angles.
Answer:
The correct option is;
Neither A nor B
Explanation:
The location of the where the thread wears in tire that has too high inflation is at the thread pattern center due to the reduced size of the contact patch with the load of the car resting on the central portion of the tire's contact surface
When the wear occurs at the outer edges of the tire, the load of the car rests on the outer edges as the contact patch increases due to the tire being under-inflated
Camber is the slope provided in road pavement to drain off water from the road
Roads with camber has a raised middle portion and wear due to camber includes outer-edge tread wear, inner-edge tread wear and tire feathering
Answer:
a) 
b) 
Explanation:
From the question we are told that:
Pressure 
Diameter 
Generally at sea level
Generally the Power series equation for Mach number is mathematically given by
Therefore
Mass flow rate
Generally the equation for Velocity at throat is mathematically given by
)
Where
Therefore
Generally the equation for Mass flow rate is mathematically given by
