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pashok25 [27]
3 years ago
14

Jane is studying the weather in Alaska. She has recorded the temperature for four days in January, in degrees Fahrenheit, as sho

wn in the table. Jane claims that as the week progressed the temperatures increased from below zero to above zero. Which of the following statements provide support for Jane's claim? Select all that apply.
Mathematics
1 answer:
solmaris [256]3 years ago
7 0

Answer: Monday had the lowest temp below zero, on Monday and Tuesday the temp was below zero.

Step-by-step explanation: I did it

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Identify the polynomial x^3-y^3+z
Vaselesa [24]

Answer:

Hi there!

The answer to this question is:

Standard: y= x- (cube root) z

the leading coefficient: 1

Step-by-step explanation:

when identifying a polynomial you always need to know the standard equation, and leading coefficient.

-you first need to know what "y" so you move y to the other side by adding it on both sides

-then you need to get y by itself and cube root it on both sides resulting in x^3 becoming x and z becoming (cube root) z

5 0
3 years ago
A store owner purchases thirty 75-watt light bulbs and 40 fluorescent light bulbs for a total cost of $95. A second purchase, at
N76 [4]

Answer:   75-watt are 30$  fluorescent are 30$ in the second and 65$ in the first

     

Step-by-step explanation: i calculated thirty 75-watt and the fluorescent and got these kinda hard to explain hope i helped:)

7 0
3 years ago
The area of a square is 225 square inches.find the length of one side
Lana71 [14]
The answer is 15inches
6 0
3 years ago
-15.6 = -3.9r<br> please include an explanation of how you got your answer :) thanks
Mumz [18]

Here is the equation:

-15.6 = -3.9r

Since both decimals are negative, the answer will be positive.

  • Negative times Negative = Positive

Divide both sides by -3.9 to leave the variable alone:

-15.6 \div -3.9  = -3.9r \div -3.9 \\ 4 = r

r is equal to 4 → r = 4

5 0
3 years ago
A billing company that collects bills for​ doctors' offices in the area is concerned that the percentage of bills being paid by
omeli [17]

Answer:

1) A. H0: p = 0.30

HA: p not equal to 0.30

2) A. The Independence Assumption is met.

C. The Randomization Condition is met.

D. The Success/Failure Condition is met.

3) Test statistic z = 2.089

P-value = 0.0367

4) C. Reject H0. There is sufficient evidence to suggest that the percentage of bills paid by medical insurance has changed.

Step-by-step explanation:

1) This is a hypothesis test for a proportion.

The claim is that there is a significant change in the percent of bills being paid by medical​ insurance.

As we are looking for evidence of a difference, no matter if it is higher or lower than the null hypothesis proportion, the alternative hypothesis is defined by a unequal sign.

Then, the null and alternative hypothesis are:

H_0: \pi=0.3\\\\H_a:\pi\neq 0.3

2) Cheking the conditions:

The independence assumption and the randomization condition are met as the bills were selected randomly from the population.

The 10% condition can not be checked, as we do not know the size of the population.

The success/failure condition is met as the products np and n(1-p) are bigger than 10 (the number of successes and failures are both bigger than 10).

3) The significance level is assumed to be 0.05.

The sample has a size n=9260.

The sample proportion is p=0.31.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.3*0.7}{9260}}\\\\\\ \sigma_p=\sqrt{0.000023}=0.005

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.31-0.3-0.5/9260}{0.005}=\dfrac{0.01}{0.005}=2.089

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z>2.089)=0.0367

As the P-value (0.0184) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there is a significant change in the percent of bills being paid by medical​ insurance.

5 0
3 years ago
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