Answer:
The maximum speed of car will be 20.5m/sec
Explanation:
We have given mass of car = 1100 kg
Radius of curve = 82.3 m
Static friction 
We have to find the maximum speed of car
We know that at maximum speed centripetal force will be equal to frictional force 

So the maximum speed of car will be 20.5m/sec
Answer:
The Meaning of Force
Meaning of Force
Force Types
Drawing Free-Body Diagrams
Meaning of Net Force
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there
Explanation:
The phases of mitosis in order from first to last are: Interphase, prophase, metaphase, anaphase, and telophase & cytokinesis.
It sounds like a special relativity question but I need more info for a total answer. But remember it's length in the lab frame is
L•sqrt(1-(v/c)^2) where L is the rest length, v is its velocity magnitude and c is the speed of light. Sqrt is the square root (I'm on a phone so I can't see the math equation editor)
The ranges of frequency are:
UVA: ![[7.50-9.38]\cdot 10^{14} Hz](https://tex.z-dn.net/?f=%5B7.50-9.38%5D%5Ccdot%2010%5E%7B14%7D%20Hz)
UVB: ![[9.38-10.71]\cdot 10^{14} Hz](https://tex.z-dn.net/?f=%5B9.38-10.71%5D%5Ccdot%2010%5E%7B14%7D%20Hz)
Explanation:
The relationship between frequency and wavelength for an electromagnetic wave is the following:

where
f is the frequency
is the speed of light
is the wavelength
For the UVA, the range of wavelength is 320 nm - 400 nm, so

So the corresponding frequencies are

For the UVB, the range of wavelength is 280 nm - 320 nm, so

So the corresponding frequencies are

So the ranges of frequency are:
UVA: ![[7.50-9.38]\cdot 10^{14} Hz](https://tex.z-dn.net/?f=%5B7.50-9.38%5D%5Ccdot%2010%5E%7B14%7D%20Hz)
UVB: ![[9.38-10.71]\cdot 10^{14} Hz](https://tex.z-dn.net/?f=%5B9.38-10.71%5D%5Ccdot%2010%5E%7B14%7D%20Hz)
Learn more about waves, frequency and wavelength:
brainly.com/question/5354733
brainly.com/question/9077368
#LearnwithBrainly