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Keith_Richards [23]
3 years ago
6

How much resistance is required to limit the current from a 12 V battery to 3.6 mA?

Physics
1 answer:
hammer [34]3 years ago
5 0

Answer:

3333.3 ohm

Explanation:

V=IR so R =V/I (in Ampere) so convert 3.6 mA to 3.6*10^-3 A

so R =12/3.6*10^-3 =3333.3

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3 years ago
If the only forces acting on a 2.0kg mass are F1 = (3i-8j)N and F2 = (5i+3j)N, what is the magnitude of the acceleration of the
belka [17]

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