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-BARSIC- [3]
3 years ago
7

What effect does solar radiation have on climate when comparing the equator to polar- regions?

Physics
1 answer:
Anarel [89]3 years ago
3 0

Answer:

The solar radiation is one of the main factors that shapes the climate all over the globe, so the climate differs with the less or more solar radiation it gets. The polar regions are cold, this is due to the fact that the solar radiation in here is very obscure, because the solar radiation falls at a very wide angle the heat is dispersed over larger area, thus the land gets very little warmth. The Equator, on the other hand, gets direct solar radiation, the sun light falls at a 90 degrees angle or close to it, so the radiation is more concentrated on a smaller area, thus the warming is bigger.

* hopefully this helps:) Mark me the brainliest:)!!!

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Which describes one event that causes an eclipse?
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earth's shadow covering the moon,thats lunar eclipse

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Quick! how did Daniel hale Williams contribute to science?
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Which word describes a goal that is poorly written?
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6 0
3 years ago
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A ball is thrown at an angle of 38 degrees to the horizontal. What happens to the magnitude of the ball's vertical acceleration
Brut [27]

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<em>I belive it is 38 degrees</em>

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Explanation:

7 0
3 years ago
A projectile is shot directly away from Earth's surface. Neglect the rotation of the Earth. What multiple of Earth's radius RE g
7nadin3 [17]

Answer:

(a) r = 1.062·R_E = \frac{531}{500} R_E

(b) r = \frac{33}{25} R_E

(c) Zero

Explanation:

Here we have escape velocity v_e given by

v_e =\sqrt{\frac{2GM}{R_E} } and the maximum height given by

\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r}

Therefore, when the initial speed is 0.241v_e we have

v = 0.241\times \sqrt{\frac{2GM}{R_E} } so that;

v² = 0.058081\times {\frac{2GM}{R_E} }

v² = {\frac{0.116162\times GM}{R_E} }

\frac{1}{2} v^2-\frac{GM}{R_E} = -\frac{GM}{r} is then

\frac{1}{2} {\frac{0.116162\times GM}{R_E} }-\frac{GM}{R_E} = -\frac{GM}{r}

Which gives

-\frac{0.941919}{R_E} = -\frac{1}{r} or

r = 1.062·R_E

(b) Here we have

K_i = 0.241\times \frac{1}{2} \times m \times v_e^2 = 0.241\times \frac{1}{2} \times m  \times \frac{2GM}{R_E} = \frac{0.241mGM}{R_E}

Therefore we put  \frac{0.241GM}{R_E} in the maximum height equation to get

\frac{0.241}{R_E} -\frac{1}{R_E} =-\frac{1}{r}

From which we get

r = 1.32·R_E

(c) The we have the least initial mechanical energy, ME given by

ME = KE - PE

Where the KE = PE required to leave the earth we have

ME = KE - KE = 0

The least initial mechanical energy to leave the earth is zero.

3 0
3 years ago
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