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2 years ago

HELP ASAP I DONT HAVE TIME IT ALSO DETECTS IF ITS RIGHT OR WRONG

Mathematics

1 answer:

storchak [24]2 years ago

5 0

Answer:

9/2*1/6=0.75

Step-by-step explanation:

hope this helped!!!!

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Which expressions are equivalent to 5x-15? Select three options.

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5(x-3) and 4x+3y-15-3y+x and -20-3x+5+8x

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I'LL GIVE BRAINLIEST....PLZ HELP ME!!

Ad libitum [116K]

Answer:

Step-by-step explanation:

y = 5x + 2.....so we will sub in 5x + 2 for y, back into the other equation

3x = -y + 10

3x = - (5x + 2) + 10

3x = -5x - 2 + 10

3x + 5x = 8

8x = 8

x = 8/8

x = 1

y = 5x + 2

y = 5(1) + 2

y = 5 + 2

y = 7

check it... (1,7)

3x = -y + 10 y = 5x + 2

3(1) = -7 + 10 7 = 5(1) + 2

3 = 3 (correct) 7 = 7 (correct)

so ur solution is : x = 1 and y = 7...or (1,7) <=====

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3 years ago

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6y-3x=-18 write it in Standard form

Vitek1552 [10]

Answer: 3x - 6y = 18

Step-by-step explanation:

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What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

Sunny_sXe [5.5K]

Answer:

First option is the correct option.

Step-by-step explanation:

$\frac{2x + 5}{ {x}^{2} - 3x } - \frac{3x + 5}{ {x}^{3} - 9x } - \frac{x + 1}{ {x}^{2} - 9 }$

Factor out X from the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x( {x}^{2} - 9)} - \frac{x + 1}{ {x}^{2} - 9}$

Using ${a}^{2} - {b}^{2} = (a - b)(a + b)$ , factor the expression

$\frac{2x + 5}{x(x - 3)} - \frac{3x + 5}{x(x - 3)(x + 3) } - \frac{x + 1}{(x - 3)(x + 3)}$

Write all numerators above the Least Common Denominators x ( x - 3 ) ( x + 3 )

$\frac{(x + 3) \times (2x - 5) - (3x + 5) - x \times (x + 1)}{x(x - 3)(x + 3)}$

Multiply the parentheses

$\frac{2 {x}^{2} + 5x + 6x + 15 - (3x + 5) - x(x + 1)}{x(x - 3)(x + 3)}$

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - x \times (x + 1)}{x(x - 3)(x + 3)}$

Distribute -x through the parentheses

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Using ${a}^{2} - {b}^{2} = (a + b)(a - b)$ , simplify the product

$\frac{2 {x}^{2} + 5x + 6x + 15 - 3x - 5 - {x}^{2} - x}{x( {x}^{2} - 9)}$

Collect like terms

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Subtract the numbers

$\frac{ {x}^{2} + 7x + 10}{ x({x}^{2} - 9)}$

Distribute x through the parentheses

$\frac{ {x}^{2} + 7x + 10}{ {x}^{3} - 9x}$

Write 7x as a sum

$\frac{ {x}^{2} + 5x +2x + 10 }{ {x}^{3} - 9x }$

Factor out X from the expression

$\frac{x(x + 5) + 2x + 10}{ {x}^{3} - 9x}$

Factor out 2 from the expression

$\frac{x( x + 5) + 2(x + 5)}{ {x}^{3} - 9x }$

Factor out x + 5 from the expression

$\frac{(x + 5)(x + 2)}{ {x}^{3} - 9x }$

Hope this helps...

Best regards!!

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