An <u>example of a problem</u> where I <em>would not</em> group the addends differently is:
3+2+4.
An <u>example of a problem</u> where I <em>would</em> group the addends differently is:
2+5+8.
Explanation:
In the <u>first problem</u>, I would not group the addends differently before adding. This is because I cannot make 5 or 10 out of any of the numbers. We group addends together to make "easier" numbers for us to add, such as 5 and 10. If we cannot do that, there is no reason to regroup the addends.
In the <u>second problem</u>, I would regroup like this:
2+8+5
This is because 2+8=10, which makes the problem "easier" for us to add. Since we can get a number like this that shortens the process, we can regroup the addends.
No. For fractions to be equal, both the numerators and denominators have to be proportional.
Since both denominators are 2, the denominators would have to be just 3 or just 4.
Answer:
F' : (-5,5)
G' : (0,5)
H' : (0,9)
Step-by-step explanation:
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Dance class is at 3:45pm, because the dance studio would not be open that early.
To make calculation easier, we first multiply
1.35 × 100 = 135
then we need to find how many groups of 5 are there in 135.
to do so, we simply take
135 ÷ 5 = 27
therefore, the answer is <u>27.</u>
