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ArbitrLikvidat [17]
3 years ago
7

Solve for x. 1/(x−4)=x/(20−5x)

Mathematics
1 answer:
Nonamiya [84]3 years ago
4 0

x=-5

Step-by-step explanation:

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Plz answer and provide explanation will choose brainliest.
Hitman42 [59]

Answer:

1500/40=37.5

D. would be your answer because all the numbers are equal or above 37.5 so Amanda can swim it in time using 40 meters per minute. If there was less time she wouldn't make the 1,500 meters.

Hope this helps

Step-by-step explanation:

7 0
3 years ago
What is the slope of the line shown?<br><br> (0,6)<br><br> (-2,0)<br> Underfined 6,3,0
Anna71 [15]

Answer:

m = 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
construct a right-angled triangle ABC where angle A =90 degree , BC= 4.5cm and AC= 7cm. please ans fast........ Very urgent. Pls
Katena32 [7]

Answer and Step-by-step explanation: The described right triangle is in the attachment.

As it is shown, AC is the hypotenuse and BC and AB are the sides, so use Pytagorean Theorem to find the unknown measure:

AC² = AB² + BC²

AB^{2} = AC^{2}-BC^{2}

AB =\sqrt{AC^{2}-BC^{2}}

AB =\sqrt{7^{2}-4.5^{2}}

AB =\sqrt{28.75}

AB = 5.4

Then, right triangle ABC measures:

AB = 5.4cm

BC = 4.5cm

AC = 7cm

6 0
3 years ago
The Sanchez family uses 2 3/4 tubes of tooth paste each month. How many tubes of toothpaste does the Sanchez family use each yea
Licemer1 [7]
2.75 * 12 = 33.

If the Sanchez family is using 2 3/4 (or 2.75) tubes of toothpaste and there are 12 months in a year, we use the equation above and get 33 as our answer.
8 0
3 years ago
Read 2 more answers
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
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