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kaheart [24]
3 years ago
14

Prove or give a counterexample: Every positive integer can be expressed as the sum of three or fewer perfect squares. (A perfect

square is an integer n for which there is an integer k with the property: n
Mathematics
1 answer:
DanielleElmas [232]3 years ago
8 0

Answer:

Statement is incorrect

Step-by-step explanation:

Every positive integer cannot be expressed as the sum of three or fewer perfect squares.

Supposing the number 7 only squares less than are 0, 1  and   4

Clearly 7 can not be written using three or fewer of these numbers

It is proved

By taking Cube root of 7

\sqrt[3]{7} = 1.912931183

Now By taking  

\sqrt{7} = 2.64575131

So both values 1.912931183 and 2.64575131 are not positive integers.

Hence the statement is incorrect.

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kvv77 [185]

Answer:

thx

Step-by-step explanation:

6 0
3 years ago
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Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
Locate the point (-3.5, -1) on the coordinate plane:
MrRissso [65]

Answer:

go to the left 3.5 units then go down one and that's your point

8 0
3 years ago
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Please help meeeeeee...
dangina [55]
Parallel means lines that never meet, and perpendicular are lines that meet at right angles.

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3 years ago
What is the domain of f(x) = √x – 4 over the set of real numbers?​
nikklg [1K]

Answer:

<u>(2) x </u>\geq \\<u> 4</u>

Step-by-step explanation:

Given the sqrt(x),  x \geq \\ zero

So, given sqrt(x -4),  x -4 \geq \\ 0

Now solve for x

x - 4 \geq \\ 0

x \geq \\ 4

6 0
3 years ago
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