<span>Warmer air is pushed upward and out of the way by cooler air.</span>
Answer:
3.0×10⁻¹³ M
Explanation:
The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.
<h3>Equation</h3>
The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.
Ksp = [Al₃⁺³]×[OH⁻]³
<h3>Solving for [Al₃⁺³]</h3>
The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.
This means the solubility product equation is ...
Ksp = x(10⁻⁷ +3x)³
For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...
3.0×10⁻³⁴ = x(10⁻⁷)³
Then x = [Al₃⁺³] will be ...
![[\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}](https://tex.z-dn.net/?f=%5B%5Ctext%7BAl%7D_3%5E%7B%5C%2C%2B3%7D%5D%3D%5Cdfrac%7B3.0%5Ctimes10%5E%7B-34%7D%7D%7B10%5E%7B-21%7D%7D%5Capprox%20%5Cboxed%7B3.0%5Ctimes10%5E%7B-13%7D%5Cqquad%5Ctext%7Bmoles%20per%20liter%7D%7D)
We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.
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<em>Additional comment</em>
The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.
Answer:
False
Explanation:
When weak bases dissociate, an equilibrium is established rather than dissociating 100%. So OH- and metal ions are partially ionized.
Answer:
Explanation:
Torr:
Torr is the measure of pressure produced by one mmHg equal to the 1/760 of standard pressure used to the pressure of vacuum system.
Millimeter mercury mmHg:
It is the manometric pressure unit. It is defined as, the pressure exerted by column of mercury one millimeter high. it is represented by mmHg.
Torr to mmHg conversion:
Both are equal to each other.
1 torr = 1 mmHg
Torr to atm:
Torr is converted into atm by dividing the torr value 760.
mmHg to atm.
mmHg is converted into atm by dividing the torr value 760.
Kilopascal:
The kilopascal is the unit of pressure. It is represented by KPa.
it is the pressure generated by 10 g mass of substance on area of 1 cm².
There are 1000 pascal in one kilopasca.
one atm = 101.325 KPa
one atm = 101325 Pa
atm can be converted into KPa by multiplying the given atm value with 101.325.
For example:
4.1 atm × 101.325 kpa/ 1 atm
415.432 atm. kpa / 1atm
415.432 kpa
Kpa to atm:
415.432 kpa/101.325 kpa × 1 atm
4.1 × 1 atm
4.1 atm