All categories

3 years ago

The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens to the pressure of

Chemistry

1 answer:

lianna [129]3 years ago

8 0

Answer:

DECREASE BY A FACTOR OF FOUR

Explanation:

Using pressure equation:

P 1 / T1 = P2 /T2 (at constant volume)

P1 = P

T1 =T

P2 = ?

T2 = 4 T

So therefore;

P2 = P1T1/ T2

P2 = P T/ 4 T

P2 = 1/4 P

The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.

You might be interested in

What types of metals require the use of a Roman numeral in the name of their iconic compounds

denis23 [38]

The answer is transition metals because they have no specific charge except for 1 or 2 of them

3 0

3 years ago

Read 2 more answers

What is the new volume if a piston starts at 25ml and 900 mm Hg and the pressure decreases to 750 mm Hg?

Oliga [24]

Answer:

I screenshot and expained here

https://screenshot.best/A7QIKV.lnk

Explanation:

8 0

3 years ago

How many grams are in 0.02 moles of beryllium iodide, Bel2?

Flura [38]

This set up of a conversion table should show you that if you multiply the grams of BeI2 times .02 moles, it equals 5.256 g (your answer)

8 0

3 years ago

in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,

insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, $H_{supplied}$ = 3.34 × 10³ J

The amount thermal energy gained by the kettle, $H_{absorbed}$ = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

$\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}} \times 100$

Therefore, we get;

$\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3} \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%$

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0

2 years ago

What compound is formed when 2,2-dimethyloxirane (2-methyl-1,2-epoxypropane) is treated with ethanol containing sulfuric acid

vladimir1956 [14]

Answer:

2-ethoxy-2-methylpropan-1-ol

Explanation:

On this reaction, we have an "epoxide" (2-methyl-1,2-epoxypropane). Additionally, we have acid medium (due to the sulfuric acid $H_2SO_4$ ). The acid medium will produce the hydronium ion ( $H^+$ ). This ion would be attacked by the oxygen of the epoxide. Then a carbocation would be produced, in this case, the most stable carbocation is the tertiary one. Then an ethanol molecule acts as a nucleophile and will attack the carbocation. Finally, a deprotonation step takes place to produce 2-ethoxy-2-methylpropan-1-ol.

See figure 1

I hope it helps!

3 0

3 years ago