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STALIN [3.7K]
2 years ago
11

What type of product is formed when acids are added to some ionic compounds?

Chemistry
1 answer:
Andru [333]2 years ago
3 0

Answer:

<em>Your</em><em> </em><em>Answer</em><em> </em><em>is</em><em> </em><em>Option</em><em> </em><em>A</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>Gas</em><em>.</em>

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How is a heterogeneous mixture different from a homogeneous mixture?
MArishka [77]
A homogeneous mixture<span> has the same uniform appearance and composition throughout. Many </span>homogeneous mixtures<span> are commonly referred to as solutions. A </span>heterogeneous mixture <span>consists of visibly </span>different<span> substances or phases. The three phases or states of matter are gas, liquid, and solid. Now this is my answer. So revise it a little. You dont want plagiarism </span>
6 0
3 years ago
PLEASE HELP What's the mass in grams of 0.442 moles of calcium bromide, CaBr2? The atomic
djverab [1.8K]

Answer: Thus there are 88.4 g of calcium bromide.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Molar mass of = 40.1 (1)+ 2(79.9) = 199.9  

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.442=\frac{x}{199.9}

x=88.4g

Thus there are 88.4 g of calcium bromide.

7 0
3 years ago
Which solution below yields the lowest final concentration of a sodium hydroxide solution prepared by diluting 50.00 mL of conce
Firdavs [7]

Answer:

The answer to your question is: letter D. 1.33 L

Explanation:

Data

V1 = 50 ml

C1 = 19.3

To solve this problem use the formula  C₁V₁ = C₂V₂

                            C2 = C1V1 / V2

C = concentration

V = volume

a) 1.15 L

                     C2 = (19.3)(50) / 1150

                      C2 = 0.84 M

b) No right answer

c) V2= 0.80 L

                     C2 = (19.3)(50) / 800

                     C2 = 1.2 M

d) V2 = 1.33 L

                        C2 = (19.3)(50) / 1330

                       C2 = 0.72 M

e) V2 = 350 ml

                         C2 = (19.3)(50) / 350

                         C2 = 2.75 M  

3 0
3 years ago
What is the concentration of a solution in which 10.0 g of AgNO3 is dissolved in 500 mL of solution?
Zigmanuir [339]

molar concentration of AgNO₃ solution = 0.118 mole/L

Explanation:

Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.

number of moles = mass / molecular weight

number of moles of AgNO₃ = 10 / 170 = 0.0588

molar concentration = number of moles / volume (L)

molar concentration of AgNO₃ solution = 0.0588 / 0.5

molar concentration of AgNO₃ solution = 0.118 mole/L

Learn more about:

molar concentration

brainly.com/question/1286583

#learnwithBrainly

6 0
3 years ago
How many electrons can the fourth energy level can accommodate? a.2 b.8 c.16 d.32​
OverLord2011 [107]

Answer:

8

Explanation:

8 0
2 years ago
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