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skad [1K]
2 years ago
12

|2| + |-13| = BRAINLIST AND EXTRA POINTS

Mathematics
2 answers:
kirza4 [7]2 years ago
8 0

Answer:

15

Step-by-step explanation:

|2| + |-13| =

2+13

15

photoshop1234 [79]2 years ago
8 0

Answer:

<h2>I think I might be 15 </h2>

Step-by-step explanation:

I looked it up on google

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Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe
Tom [10]

Answer:  The correct option is (B) f(q) = 2q + 3.

Step-by-step explanation:  The given equation representing a function is

6q=3s-9~~~~~~~~~~~~(i)

We are to write the equation in function notation with 'q' as independent variable.

From equation (i), we have

6q=3s-9\\\\\Rightarrow 3s=6q+9\\\\\Rightarrow s=2q+3.

So, 's' can be represented as a function of 'q'. Hence, we can write

s=f(q).

Therefore, we have

f(q)=2q+3.

Thus, (B) is the correct option.

7 0
2 years ago
-1/2 ^5 =<br><br> Solve as a Fraction
Oksanka [162]

Answer:

-1/32

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Right triangle ABC is reflected over AC, then dilated by a scale factor 2/3 to form triangle DEC. Which statements about the two
kodGreya [7K]

Answer:

The answer is "all angle will be same"

Step-by-step explanation:

In the given question choices were missing so, the correct choice can be defined as follows:

Given:

ABC reflected over AC and dilated by a scale factor 2/3 from ΔDEC.

Solution:

\triangle  ABC  \sim  \triangle  DEC \angle B \cong  \angle E3DE = 2AB

7 0
3 years ago
Whats the answer for (5x + 8)(4x² + 6x - 8)
mestny [16]
(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\

The final result is: 20x^3 + 62x^2 + 8x - 64.
4 0
3 years ago
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
2 years ago
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