Answer: Phosphodiester bond
Explanation:
The backbone of DNA consists of deoxyribose nucleotides linked by phosphodiester bridges.
The 3'-hydroxyl of the adjacent sugar of one deoxyribonucleotide is joined to the 5'-hydroxyl of the adjacent sugar by an internucleotide linkage called a phosphodiester bond.
Thus, phosphodiester bond is the answer
Answer:
C. Chlamydia. is the correct answer.
Explanation:
Chlamydia is a bacterial sexually transmitted disease, caused by obligate intracellular Chlamydia trachomatis.
In the life of chlamydia, there are two stages of developmental(Reticulate and elementary bodies are two forms of Chlamydia.)
The elementary body is the infectious substance, they are non replicating and have a rigid outer membrane that binds to the receptors present on the host cell and it initiates the infection and due to the rigid outer membrane there, no fusion between the phagosome and the lysosome hence oppose the intracellular killing.
Reticulate bodies are the metabolically active form of a chlamydia and non-infectious.
The mantle has properties of both liquids and solids
Answer:When a wound causes bleeding, the body responds with a positive feedback loop to clot the blood and stop blood loss. Substances released by the injured blood vessel wall begin the process of blood clotting
Explanation:
Dna sugar- deoxyribose
Rna sugar- ribose
DNA base- thymine
RNA base- uracil
DNA location- nucleus
RNA location- cytoplasm/nucleus/ ribosomes
