Answer:

The domain of the inverse of a relation is the same as the range of the original relation. In other words, the y-values of the relation are the x-values of the inverse.
Thus, domain of f(x): x∈R = range of f¯¹(x)
and range of f(x): x∈R =domain of f¯¹(x)
Answer:
5x³ - 2x² - 5x + 8
Step-by-step explanation:
[ Refer to the attachment ]
Y° = y₁° (opposite or Vertical angles), but y₁ = 45° corresponding angles,
then y = 45°
Horizontal distance = 48'
difference in elevation = 18"-6" = 12" = 1'
Slope of the sewer line = rise/run = 1/48 = 0.0208 = 2.08%