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Nana76 [90]
3 years ago
14

.

Mathematics
1 answer:
BabaBlast [244]3 years ago
8 0

Answer: 14.88 is the answer

Step-by-step explanation:

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How do I find the product when multiplying with decimals<br><img src="https://tex.z-dn.net/?f=0.36%20%5Ctimes%202.4" id="TexForm
stellarik [79]

Step 1:

first let us convert the two decimals into fractions.

0.36=36/100 (since there are two digits after decimal point we divide by 100)

2.4=24/10 (since there are one digit after decimal point we divide by 10)

now we can multiply the fractions

\frac{36}{100}×\frac{24}{10}

multiplying numerator with numerator and denominator with denominator:

\frac{36*24}{100*10}

=\frac{864}{1000}

Now we can convert this back to decimal

864/1000=0.864, moving decimal three digits to the left since we have three zeros in the denominator that is 1000.

Answer=0.864

7 0
3 years ago
Tank A initially contained 124 liters of water.
Taya2010 [7]

The following amounts of water have not been listed.

However, to find m all you need to do it;

the amount of water which is in the tank - 124 = x

x ÷ 9 = m

4 0
3 years ago
What is the midpoint of QR. Q(2,4) and R(-3,9)
Eduardwww [97]

Answer:

The answer is

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q(2,4) and R(-3,9)

The midpoint is

M = ( \frac{2 - 3}{2}  \:  , \:  \frac{9 + 4}{2} ) \\

We have the final answer as

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Hope this helps you

6 0
3 years ago
What are some HARD math facts that equal 100
Lelu [443]
0.10 *1000 = 100

0.2 * 500 = 100
6 0
3 years ago
??!?!?!?!?!!?!?!?!!?!!!?!!!!?
Nikitich [7]

Answer:

The third option, a rational number

like 1/5 + 2.5 is still rational (but neither irrational nor whole/an integer)

it would be 0.2 + 2.5 = 2.7 btw

or

1/5 + 5/2

= 2/10 + 25/10

= 27/10

6 0
3 years ago
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