.

Mathematics

1 answer:

BabaBlast [244]2 years ago

8 0

Answer: 14.88 is the answer

Step-by-step explanation:

You might be interested in

A chef uses 2 tablespoons of olive oil for every 3 tablespoons of butter. How much olive oil is needed for each tablespoon of bu

BigorU [14]

Answer: 2/3

Step-by-step explanation: You take the 2 and divided it by 3 but your going to get a long decimal so you can put it into a fraction of 2/3

6 0

3 years ago

Read 2 more answers

Please Help!!! I'll make you Brainliest!!! Thanks :)

Romashka-Z-Leto [24]

The answer for the second one is 0.

8 0

3 years ago

Read 2 more answers

What is the domain of the function y=

alex41 [277]

Step-by-step explanation:

answer and explanation is pinned

4 0

2 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

3 years ago

In the military, 1/4 of an enlisted person's time is spent sleeping and eating, 1/12 is spent standing at attention, 1/6 is spen

IRINA_888 [86]

All you have to do is add all of the fractions up.

5 0

3 years ago