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3 years ago

CAN SOMEONE HELP ME?? THANKS!!!

Mathematics

1 answer:

joja [24]3 years ago

3 0

Answer:

the one thats not equal to 16 is the last one; 8^2

Step-by-step explanation:

all of them equal 16 but 8^2 is 64

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On the day a coffee shop first opened, it had 140 customers. 65% of the customers ordered a large coffee.

Leviafan [203]

140/100 * 65 = 91 people
Divide 140 by 100 to find 1 percent then multiply by 65 to find 65 percent.

8 0

3 years ago

Read 2 more answers

A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af

fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = $T+(T_0-T)e^{-kt}$

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

$T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110$

So equation is

$T(t) = 40+(30)e^{-0.8110t}\\$

When t=1,

we get

$T(1) = 40+(30)e^{-0.8110}\\\\=53.3324$

5 0

3 years ago

Which graph is a one-to-one function?

matrenka [14]

Answer:B

Step-by-step explanation:

6 0

2 years ago

What is equivalent to radical 40

Lana71 [14]

Answer:

2sqrt(10)

Step-by-step explanation:

radical 40

I rewrite this as sqrt(40) It means the same thing

sqrt(40)

sqrt(4*10)

We know that sqrt(a *b) = sqrt(a) sqrt(b)

sqrt(4) sqrt(10)

2sqrt(10)

5 0

3 years ago

Wasserman (1989) studied a process for the manufacturing of steel bolts. Historically, these bolts have a mean thickness of 10.0

zalisa [80]

Answer:

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

Step-by-step explanation:

To solve this question, we use the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 10, \sigma = 1.6, n = 5, s = \frac{1.6}{\sqrt{5}} = 0.7155$

The mean of of the sample mean of these quality checks is 10 and the standard deviation is 0.7155.

7 0

3 years ago