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stira [4]
3 years ago
11

Neil measures the lengths of some objects in both yards and feet.

Mathematics
1 answer:
Elodia [21]3 years ago
3 0
The constant of proportionality is 3 (multiplied by 3 to be exact)
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X²-10x+25=0 quadratic equation by factoring​
lisov135 [29]

Answer:

x = 5

Step-by-step explanation:

{x}^{2}  - 10x + 25 = 0 \\  {x}^{2}  - 5x - 5x + 25 = 0 \\ x(x  -  5) - 5(x - 5) = 0 \\ (x - 5)(x - 5) = 0 \\ ( x- 5) = 0 \: or \: (x - 5) = 0 \\ x = 5 \: or \: x = 5 \\ x = 5

4 0
3 years ago
Dr. Tu must administer emergency medicine to his patient, Mrs. Jones. The
galben [10]

Answer:

168

Step-by-step explanation: You would do 140/100 = 1.4 then multiply 120 by 1.4 which is 168.

3 0
3 years ago
Which polynomial function could be represented by the graph below?
Fantom [35]

Answer:

x2 + x – 2=4x

sorry if i give you the wrong answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Describe how to transform (5 square root x^7)^3
Serga [27]
(5 * sqrt(x^7))^3

Recall sqrt(x^2)=x

So we get (5*x^6 )^3

5*3 is 25, 6*3 is 18 (and exponent to an exponent multiplies)

Therefore the answer is 25x^18
7 0
3 years ago
If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?​
enyata [817]

Step-by-step explanation:

\bf➤ \underline{Given-} \\

\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\

\bf➤ \underline{To\: find-} \\

\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\

\bf ➤\underline{Solution-} \\

<u>Let us assume that:</u>

\rm: \longmapsto u =  {x}^{2013}

<u>Therefore, the equation becomes:</u>

\rm: \longmapsto u +  \dfrac{1}{u}  = 2

\rm: \longmapsto \dfrac{  {u}^{2} + 1}{u}  = 2

\rm: \longmapsto{u}^{2} + 1 = 2u

\rm: \longmapsto{u}^{2} - 2u + 1 =0

\rm: \longmapsto  {(u - 1)}^{2} =0

\rm: \longmapsto u = 1

<u>Now substitute the value of u. We get:</u>

\rm: \longmapsto {x}^{2013}  = 1

\rm: \longmapsto x = 1

<u>Therefore:</u>

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 1 + 1

\rm: \longmapsto {x}^{2022}  +  \dfrac{1}{ {x}^{2022} }  = 2

★ <u>Which is our required answer.</u>

\textsf{\large{\underline{More To Know}:}}

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0
3 years ago
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