Answer:
A)3
Step-by-step explanation:
Answer:
Domain (0, ∞)
Range (-∞, ∞)
Step-by-step explanation:
The domain is the input values
The input is from 0 to infinity
Domain (0, ∞)
The range is the output values
The input is from negative infinity to infinity
Range (-∞, ∞)
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
9514 1404 393
Answer:
17/99
Step-by-step explanation:
Replace the digits 23 in your example with the digits 17 and you have your answer:
_____
In general, a 2-digit repeat will have 99 as its denominator. If the digits are a multiple of 3 or 11, then the fraction can be reduced. 17 is prime, so the fraction cannot be reduced.
Answer:
6.4 kmph
Step-by-step explanation:
12.8/2=6.4 kmph
