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natka813 [3]
3 years ago
10

Pls pls help I will mark BRAINLIST

Mathematics
1 answer:
lesantik [10]3 years ago
4 0

Answer:

54π

Step-by-step explanation:

To find the volume of the cylinder, you will be using V=π(r^2)h

r = radius = 3

h = height = 6

V = π(3^2)(6) = 54π

The bracket means to multiply.

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The average distance from Mars to the sun is about one hundred forty- one million, six hundred twenty thousands miles. How is th
gavmur [86]

Answer: 141,620,000

<u>Step-by-step explanation:</u>

one hundred forty-one million, six hundred twenty,  thousands

                       ↓                                       ↓                            ↓

                     141,                                    620,                      000  

5 0
3 years ago
HELP!!! this is graded and no links plzzzzz!!!!!
vampirchik [111]

Answer:

88cm^2

Step-by-step explanation:

Area of the rectangle: base x height

Area of parallelogram: base x height

Area of the shaded part: area of rectangle -area of parallelogram:

12x10-4x8=120-32=88

5 0
2 years ago
Please help with this algebra
scoray [572]

Answer:

A

Step-by-step explanation:

ddhxhdhdnxkajsbxdjdhcch

7 0
3 years ago
T(z)= sin^2(z/4), {-3 ≤ z ≤ 8}
Usimov [2.4K]

Answer:

T´(z)=n^2s/4*i

Step-by-step explanation:

T(z)=d/dz(sin^2*z/4)

T´(z)=d/dz(sn^2zi/4)

T´(z)=d/dz(sn^2z/4*i)

T´(z)i*d/dz(sn^2z/4)

T´(z)=n^2s/4*i

Simplify

3 0
3 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
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