Answer:
V = 0.248 L
Explanation:
To do this, use the following equation:
P1*V1/T1 = P2*V2/T2
This equation is used to find a relation between two differents conditions of a same gas, which is this case. From this equation we can solve for V2.
Solving for V2:
V2 = P1*V1*T2/T1*P2
Temperature must be at Kelvin, so, we have to sum the temperature 273 to convert it in K.
Replacing the data we have:
V2 = 1 * 4.91 * (-196+273) / 5.2 * (20+273)
V2 = 378.07 / 1523.6
V2 = 0.248 L
Answer:
Explanation:
F=kx
x=F/k
F=2000 kg
x=100 cm=9*10^-3
effective spring constant=k=F/x
k=2000/9*10^-3=2.2*10^-5
now frequency
f=1/2π√k/m
f=1/2*3.14√2.2*10^-5/310
f=1/6.28√7.097*10^-8
f=1/6.28*2.7*10^-4
f=0.16*2.7*10^-4
f=4.32*10^-5
Send wave from your location to the object and wait until echo is back.
Measure the time taken.
If you know the speed of wave (say sound wave), than just multiply by half time taken wave to return
gurlll this need way more points
Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:
where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,
T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:
where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,
<u>g = 11.2 m/s²</u>
