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3 years ago

7

a steam engine works on its vicinity and 285k heat is released with the help of 225C energy absorbed to the system. what is the

efficiency of steam engine?explain the use of rest of energy

1 answer:

Sedaia [141]3 years ago

7 0

Explanation:

define the term specific heat capacity of water

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If a car drives 10 mph South, this is an example of a:

nekit [7.7K]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

1. In which direction can a force be exerted on an object?

My name is Ann [436]

A. Any Direction
This should be obvious, as you can push down on something, push it to the sides, and push something up. Hope this helped!

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4 years ago

Which of the following quantities has the same dimensions as a speed? and why?

saveliy_v [14]

Answer:

the answer is at

Explanation:

Dimension of at = [ LT^-2 ] [ T ]

= [ LT^(-2+1) ]

= [ LT^-1 ]

which is same as dimension of speed.

6 0

3 years ago

A star's brightness as if it were a standard distance from Earth (10 parsecs) is known as what? radiation apparent brightness li

aleksley [76]

Answer:

In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).

Explanation:

8 0

3 years ago

The coefficient of friction between a rider and the merry go round is 0.45 and the person is measured to be traveling at 20.0 RP

svlad2 [7]

The person must stand at a radius of 0.99 m

Explanation:

In order for the person to stand on the merry go round, the force of friction acting on the person must provide the centripetal force necessary to keep the person in uniform circular motion.

Therefore, we can write:

$\mu mg = m\omega^2 r$

where:

- the term on the left is the force of friction, and the term on the right is the centripetal force

$\mu = 0.45$ is the coefficient of friction

m is the mass of the person

$g=9.8 m/s^2$ is the acceleration of gravity

$\omega = 20 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=2.09 rad/s$ is the angular velocity

r is the radius of the circular path

Solving the equation for r, we find the radius at which the person must be standing:

$r=\frac{\omega^2}{\mu g}=\frac{(2.09)^2}{(0.45)(9.8)}=0.99 m$

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

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3 years ago