Answer:
Weight = 3.92 N
Explanation:
Given:
Mass m = 0.4 kg
Acceleration due to gravity g = 9.8 m/s²
Find:
Weight
Computation:
Weight = Mass x Acceleration due to gravity
Weight = 0.4 x 9.8
Weight = 3.92 N
A line from second to home creates a right triangle with 45 degree angles.
This makes the diagonal line the side length of the square multiplied by the sqrt(2)
Second to home = 90sqrt(2) = 127.279 feet ( round answer as needed)
Answer:
Grounded used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Explanation:
A grounded conductor is referred to as one of the wire that needed in an electric circuit. it is basically a neutral conductor. It used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.
As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.
Oxygen is diatomic, so its degree of freedom, (f1)= 5,
also its number of moles, n1= 1
Helium is monoatomic, so its degree of freedom (f2)= 3
and its number of moles given is, n2=2
Now using formula of effective degree of freedom of mixture, (f), we have:
f= (f1n1+f2n2)/(n1+n2)
= (5*1 + 3*2)/ (1+3)
=11/3
Also, from first law of thermodynamics;
U= n Cv. T = nRT(f2)
or, Cv = R. (f/2) (n & T cancel)
We know f=11/6,
substituting the value in above relation, we have:
Cv= R. 11/3*2
= R. 11/6
Also, Cp-Cv = R
or, Cp- R.(11/6)= R
or, Cp= R(11/6 )+1
= 17/6 R
Therefore, Cp/Cv = 17/11
Answer:
0.5 m/s
Explanation:
From Newton's Third law of motion,
Momentum of the cannon = momentum of the flatcar.
mv = MV........................ Equation 1
Where m = mass of the cannon, v = velocity of the cannon, M = mass of the flatcar, V = Velocity of the flat car.
make V the subject of the equation
V = mv/M................... Equation 2
Given: m = 10 kg, v = 50 m/s, M = 1000 kg
Substitute into equation 2
V = 10×50/1000
V = 500/1000
V = 0.5 m/s
Hence the speed of the flatcar = 0.5 m/s
