Maurice is playing some of the arcades at the county fair. At one booth he throws a 1.2-kg ball forward with a velocity of 15 m/
s and hits a 0.5-kg can
at rest. The ball continues forward at 9 m/s. What is the new velocity of the can, in m/s? (Round your answer to one decimal place if necessary.)
at rest. The ball continues forward at 9 m/s. What is the new velocity of the can, in m/s? (Round your answer to one decimal place if necessary.)
1 answer:
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Answer:
θ_c = 24.4º
Explanation:
To find the critical angle, let's use the law of refraction where index 1 refers to the incident medium (diamond) and index 2 refers to the medium where it is to be refracted (air)
n₁ sin θ₁ = n₂ sin θ₂
for the critical angle the ray comes out refracted parallel to the surface, therefore the angle is
θ₂ = 90
n₁ sin θ₁ = n₂
θ_c = θ₁ = sin⁻¹
the index of refraction of the diamond is tabulated
n₁ = 2.419
let's calculate
θ_c = sin⁻¹ ()
θ_c = 24.4º