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bearhunter [10]
3 years ago
5

Which of the following choices is a single-replacement reaction? A. 2K + Br2 2KBr B. 2H2 + O2 2H2O C. Mg + FeO Fe + MgO D. C + 2

Cl2 CCl4
Physics
1 answer:
Otrada [13]3 years ago
5 0
A single replacement reaction occurs when two different cations switch places to combine with the same anion. One element forms a compound while another element is released from the compound. In a single replacement reaction, or single displacement reaction, a single<span> uncombined element replaces another in a compound.

So you're answer is probably c.
</span>
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Calculate the electric field intensity at a point 3 cm away from point charge of 3 x 10^-9 C.
lukranit [14]

Answer:

The electric field intensity is <u>30000 N/C.</u>

Explanation:

Given:

Magnitude of the point charge is, q=3\times 10^{-9}\ C

Distance of the given point from the point charge is, d=3\ cm=0.03\ m

Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.

Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:

E=\frac{kq}{d^2}

Plug in k=9\times 10^9\ N\cdot m^2/C^2, q=3\times 10^{-9}\ C, d=0.03\ m. Solve for 'E'.

E=\frac{(9\times 10^9\ N\cdot m^2/C^2)(3\times 10^{-9}\ C)}{(0.03\ m)^2}\\\\E=\frac{27}{0.0009}\ N/C\\\\E=30000\ N/C

Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.

3 0
3 years ago
I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
777dan777 [17]

Answer:

idek to be honest

Explanation:

4 0
2 years ago
Read 2 more answers
The journey of an electron through an external circuit involves a long and slow zigzag path that is characterized by losses in e
Kitty [74]

Answer:

d_{b} = 2 d_{a}

Explanation:

The electrical resistance for a cylindrical wire is described by the expression

         R = ρ L / A

The area of ​​a circle is

     A = π r²

     r = d / 2

     A = π d²/4

We substitute

      R = ρ L  4 /π d²

Let's apply this expression to our case, they indicate that the resistance of wire A is 4 times the resistance of wire B

    R_{a} = 4 R_{b}

We substitute

    ρ  4/π d_{a}² = 4 (ρ  4/π d_{b}²)

    1 / d_{a}² = 4 / d_{b}²

     d_{a} = d_{b} / 2

4 0
2 years ago
Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
Roman55 [17]

Answer:

0.8 N

Explanation:

From coulomb's law,

Formula:

F = kqq'/r²........................ Equation 1

Where F = Force of repulsion, k = coulomb's constant, q = first positive charge, q' = second positive charge, r = distance between the charge.

Given: q = 20 μC = 20×10⁻⁶ C, q' = 100 μC = 100×10⁻⁶ C, r = 150 cm = 1.5 m.

Constant:  k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = (20×10⁻⁶ )( 100×10⁻⁶)(9×10⁹)/1.5²

F = 1800×10⁻³/2.25

F = 1.8/2.25

F = 0.8 N

3 0
3 years ago
Strongest Element on Earth
Alex777 [14]

Tungsten has the highest tensile strength of any natural metal, but it's brittle and tends to shatter on impact.

Titanium has a tensile strength of 63,000 PSI. ...

Chromium, on the Mohs scale for hardness, is the hardest metal around.

8 0
3 years ago
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