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insens350 [35]
3 years ago
9

E

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

10.35 miles in 1 hout

Step-by-step explanation:

I'm Sorry if this wrong.

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when a relation is drawn on an xy-plane what is another name for the set of all x values from its graph?
Galina-37 [17]

Another name for the set of all x-values for a relation is: domain.

<h3>What is the Domain of a Relation?</h3>

The domain of a relation can be defined as all the x-values that corresponds to the y-values that are plotted on a graph.

They are referred to as the input or the domain of the relation. Therefore, another name for the set of all x-values plotted for a relation on a graph is: domain.

Learn more about domain on:

brainly.com/question/26098895

#SPJ1

7 0
2 years ago
Question and choices Are below
Vika [28.1K]

Answer:

9ft

Step-by-step explanation:

Use the pythagorean theorem.

15^2 = 12^2 + x^2

solve for x

x^2 = 81

x = 9

7 0
3 years ago
james attached a diagonal brace across a rectangular frame that measures 6ft by 8ft what is the length of the diagonal brace
Bogdan [553]
To solve this you would use the pythagorean theorem since the brace is making the frame look like two right triangles. The theorem states that for a triangle with a right angle, A^2+B^2=C^2. A and B are the sides of the frame and C is the brace which is like the hypotenuse of the triangle. It doesn't matter which side is A or B so you can put 6 or 8 in place of either in the equation. 6^2+8^2=C^2. If you simplify this it equals 36+64=C^2, which then simplifies to 100=C^2. Then you take the square root of both sides (what number multiplied by itself = the number you are trying to get, in this case, 100). So then you get C=10 because 10x10=100. So the length of the diagonal brace is 10ft.
4 0
3 years ago
HELPP my work is due soon plus i don’t understand :(
Mashcka [7]

Answer:

4. B

5.

Step-by-step explanation:

8 0
3 years ago
Find the focus for y=x^2+4x-7
padilas [110]

ANSWER

(2,-10.75)

EXPLANATION

The given function is

y =  {x}^{2}  - 4x - 7

We rewrite this function to obtain,

(y + 11) =  {( x- 2)}^{2}

We now compare this function to

(y  -  k) = 4p {( x- h)}^{2}

We have

4p = 1

This implies that,

p =  \frac{1}{4}

The vertex is (2,-11).

The focus is

(2,-11+ \frac{1}{4} )

(2,- \frac{43}{4} )

(2,-10.75)

7 0
3 years ago
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