Answer:
m = 1125.9 g.
Explanation:
Hey there!
In this case, according to the given information, it turns out possible for us to solve this problem by using the definition of density as mass divided by volume:
Thus, we solve for the mass in the equation to obtain:
Then, we plug in the values to obtain:
Regards!
The correct answer is A I believe
The answer is; active transport
This means that energy is expended in the process. Because large protein cannot be transported through protein channels in the plasma membrane for being too big, they are transported through endocytosis. This means a vesicle merges with the plasma membrane and forms an invagination that engulfs the protein. The vesicle then encloses with the protein inside and moves into the cell.
(2.03x10^22)/(6.02x10^23) = .033721 mol Li
I hope this helps, if not, i am sorry
<h3>Answer:</h3>
Excess Reagent = NBr₃
<h3>Solution:</h3>
The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,
2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO
Calculating the Limiting Reagent,
According to Balance equation,
2 moles NBr₃ reacts with = 3 moles of NaOH
So,
40 moles of NBr₃ will react with = X moles of NaOH
Solving for X,
X = (40 mol × 3 mol) ÷ 2 mol
X = 60 mol of NaOH
It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.
