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kow [346]
1 year ago
10

What is the name of a substance that contains a useful element which can be extracted from it?

Chemistry
1 answer:
dalvyx [7]1 year ago
7 0

The name of a substance that contains a useful element which can be extracted from it is ore.

ore can be defined as the mineral from which useful substance can be extracted and it contains more valuable substances. ore is deposited of one or more precious mineral in earth crust.  examples of ore is iron ore : hematite , magnetite , copper ore : pyrite , borntite, zinc ore : sphalerite, zinc blende, calamite.

The Four types of ore  are given as follows :

  • Ore oxide
  • Ore halides
  • Ore carbonates
  • sulphide ore

Thus, The name of a substance that contains a useful element which can be extracted from it is ore.

To learn more about ore here

brainly.com/question/4712893

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3 years ago
Refer to the Chemical Compounds table above. How many total elements are in<br> Ethanol?
Korolek [52]

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3 element i.e carbon (C), hydrogen (H) and oxygen.

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Subtance >>>>>>>> Chemical Formula

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8 0
3 years ago
Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:
rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

PV=nRT

n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of  water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

P'V'=n'RT'

n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol

CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

\frac{3}{1}\times 0.6402 mol=1.9208 mol of hydrogen gas

Moles of hydrogen gas obtained theoretically = 1.9208 mol

The reaction produces 26.0 L of hydrogen gas measured at STP.

At STP, 1 mole of gas occupies 22.4 L of volume.

Then 26 L of volume of gas will be occupied by:

\frac{1}{22.4 L}\times 26 L= 1.1607 mol

Moles of hydrogen gas obtained experimentally = 1.1607 mol

Percentage yield of hydrogen gas of the reaction:

\frac{Experimental}{Theoretical}\times 100

\%=\frac{ 1.1607 mol}{1.9208 mol}\times 100=60.42\%

60.42% is the percent yield of the reaction.

8 0
3 years ago
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