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kow [346]
1 year ago
10

What is the name of a substance that contains a useful element which can be extracted from it?

Chemistry
1 answer:
dalvyx [7]1 year ago
7 0

The name of a substance that contains a useful element which can be extracted from it is ore.

ore can be defined as the mineral from which useful substance can be extracted and it contains more valuable substances. ore is deposited of one or more precious mineral in earth crust.  examples of ore is iron ore : hematite , magnetite , copper ore : pyrite , borntite, zinc ore : sphalerite, zinc blende, calamite.

The Four types of ore  are given as follows :

  • Ore oxide
  • Ore halides
  • Ore carbonates
  • sulphide ore

Thus, The name of a substance that contains a useful element which can be extracted from it is ore.

To learn more about ore here

brainly.com/question/4712893

#SPJ1

You might be interested in
Which of the following is true for an excess reactant?
kupik [55]

Answer:

C) It is the reactant that is left over after the reaction stops.

Explanation:

The excess reactant is the reactant that is left over after the reaction stops. The extent of the reaction is not determined by this reactant.

A limiting reactant is a reactant that is in short supply within a given reaction.

Such reactants determines the extent of chemical reaction.

  • Limiting reactants are used up in a chemical reaction.
  • The excess reactants remains unchanged after the reaction.
8 0
3 years ago
A 5.0 L sample of gas at 300. K is heated to 600. K. What will the new volume of the gas be?
Ainat [17]

Answer:

V_2=10L

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:

\frac{V_2}{T_2} =\frac{V_1}{T_1}

In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:

V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L

Regards!

4 0
2 years ago
How many liters of O2 at 298 K and 1.00 bar are produced in 1.50 hr in an electrolytic cell operating at a current of 0.0200 A?
stellarik [79]

Answer: 0.0069L

Explanation:

2H2O(l) ---->O2(g) + 4H+(aq) + 4e-

no of moles= it/eF

NO of moles of O2 produced = (Current in Ampere x Time in second)/ (Faraday constant x Number of electrons required)

Moles of O2 produced = (0.02x (60 x 60X1.5 s)/(96485 x 4)

= 0.0002798 moles= 2.798x 10 ^-4moles

Using  ideal gas equation,

P V = n R T

Where, P is the pressure,

V is the volume,

n is the number of moles,

R is the gas constant, and T is the temperature

We have, 1 bar = 0.986923 atm

Substituting the values,

V = nRT/P = (2.798 x 10-4moles x 0.08205 L atm mol K x 298 K)/ 0.986923 atm = 0.0069L

Volume of O2 produced = 0.0069L

7 0
3 years ago
9. Describe two ways in which you can conserve and recycle lab resources.<br> I
Law Incorporation [45]

Answer:

Using solar energy, hydroelectric energy and wind are major ways of conserving natural resources. Trees and other organic energy sources are traditional sources of renewable energy. Forests can be replanted and hemp and other organic materials such as ethanol can be used to preserve natural resources.

4 0
3 years ago
8. When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. I
Julli [10]

Hey there!:

8) ΔTb = i*Kb*m  

 m is molality

 Since same number of mol is added to same amount of water in both cases

m will be same for both

is 1 for glucose since it is covalent compound

is 4 of Al(NO3)3 as it breaks into 1 Al₃⁺ and 3 NO₃⁻

So,  ΔTb will be 4 times in aluminum nitrate case

So, boiling point will change by 4ºC


9) use Q = m*  L

L =  heat of vaporization so:

T1=T2=100ºC

5.40 * 1000 => 5400  cal/g

Q =   5400 / 540

Q = 10 grams


Hope that thlps!

5 0
3 years ago
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