The answer will be 3 over 2 which mean 3/2
Company A:
c = 40 + 2s
Company B:
c = 20 + 4s
Equal costs => 40 + 2s = 20 +4s => 4s - 2s = 40 - 20 => 2s = 20 => s = 20/2
=> s = 10
And c = 20 + 4s = 20 + 4(10) = 20 + 40 = 60
Answer: 10 videos
Answer: (-2, 0) and (0, -2)
Step-by-step explanation:
This system is:
y + x = -2
y = (x + 1)^2 - 3
To solve this we first need to isolate one of the variables in one fo the equations, in the second equation we have already isolated the variable y, so we can just replace it in the first equation:
(x + 1)^2 - 3 + x = -2
Now we can solve this for x.
x^2 + 2*x + 1 - 3 = -2
x^2 + 2*x + 1 -3 + 2 = 0
x^2 + 2*x + 0 = 0
The solutions of this equation are given by the Bhaskara's formula, then the solutions are:
The two solutions are:
x = (-2 - 2)/2 = -2
In this case, we replace this value of x in the first equation and get:
y - 2 = -2
y = -2 + 2 = 4
This solution is x = -2, y = 0, or (-2, 0)
The other solution for x is:
x = (-2 + 2)/2 = 0
If we replace this in the first equation we get:
y + 0 = -2
y = -2
This solution is x = 0, y = -2, or (0, -2)
Answer:
0.85
Step-by-step explanation:
The interquartile range of any given data set is simply the difference between the Q3 and the Q1, i.e. Q3 - Q1.
Let's find the Q3 and the Q1 of the given data set: 30.8, 29.9, 30.0, 31.0, 30.1, 30.5, 30.7, 31.0
First, let's order the data given in increasing order from small to the largest value:
29.9, 30.0, 30.1, 30.5, 30.7, 30.8, 31.0, 31.0
Let's find the median:
Since the number of data set given is even number (8), our median would be the average of the 4th and 5th data value = (30.5+30.7) ÷ 2 = 30.6
Let's find Q3 and Q1
Q1 is the middle value from the median point to our left = (30.0+30.1) ÷ 2 = 30.05
Q3 is the middle value from the median point to our right = (30.8+31.0)÷2 = 30.9
Interquartile Range = 30.9 - 30.05 = 0.85