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4 years ago

Which of these mixtures would be easiest to separate?

Physics

1 answer:

Nimfa-mama [501]4 years ago

7 0

A. Fruit salad because you can just remove it from the cup or bowl

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What is the thinnest film of MgF₂ (n = 1.38) on glass that produces a strong reflection for orange light with a wavelength of 60

marysya [2.9K]

Answer:

Thickness is 217 nm

Explanation:

For a thin film, constructive and destructive interference each has its own effects. Here constructive interference causes the light to be strongly reflected. The thickness can be determined from

$2\times t\times n \times sin\theta=m\lambda$

here n is refractive index 1.38, m=1 , $\theta$ =0, $\lambda$ =600 nm

$t=\frac{600 \times 10^{-9}}{2\times 1.38} \\t=217 nm$

4 0

4 years ago

Using the equation T=2π√L/g solve for L

weqwewe [10]

You said T = 2 · π · √(L / g)

(I think that's the formula for the full-swing period of a simple pendulum.)

Divide each side by 2π : T/2π = √(L / g)

Square each side: (T/2π)² = L / g

Multiply each side by ' g ' : L = g · (T/2π)²

4 0

3 years ago

How is blood flow related to lung function during exercise

skelet666 [1.2K]

The relationship of blood flow to lung function during exercise is that the blood flow in the lungs and other parts of the body is increased when a person is exercising. ... Blood travels faster from the lungs to the different parts of the body because the heart pumps faster to the lungs.

7 0

3 years ago

In the laboratory a "coffee cup" calorimeter, or constant pressure calorimeter, is frequently used to determine the specific hea

VMariaS [17]

Answer:

$c_{e1}$ = 128.3 J / kg ° C

Explanation:

In this exercise we will use that the expression for heat is

Q = m $c_{e}$ ΔT

As they indicate that there are no losses with the medium, the heat transferred by the tungsten is equal to the heat absorbed by the water plus the calorimeter

Q assigned = QAbsorbed

Q hot = Q cold + Q calorimeter

The mass of tungsten (m₁ = 69.12 10⁻³ kg) with an initial temperature (T₁ = 98.93°C),

The mass of water (m₂ = 85.45 10⁻³ kg) at a temperature (T₂ = 23.82°C),

a calorimeter constant (C = 1.56 J/ °C)

m₁ $c_{e1}$ (T₁ - $T_{f}$ ) = (m₂ $c_{e2}$ + C) ( $T_{f}$ - T₂)

$c_{e1}$ = (m₂ ce2 + C) ( $T_{f}$ -T₀) / (m₁ (T₁- $T_{f}$ )

$c_{e1}$ = (85.45 10-3 4186 + 1.56) (25.63 - 23.82) / (69.12 10-3 (98.93 - 25.63))

$c_{e1}$ = (357.69 + 1.56) 1.81 / (69.12 10-3 73.3)

$c_{e1}$ = 650.24 / 5.0665

$c_{e1}$ = 128.3 J / kg ° C

6 0

3 years ago

Is equivalent resistance the same as total resistance

Llana [10]

Answer:

hope it helps

please brainliest

8 0

3 years ago