Answer:
I(x)  = 1444×k ×
I(y)  = 1444×k ×
I(o) = 3888×k × 
   
Explanation:
Given data
function =  x^2 + y^2 ≤ 36
function =  x^2 + y^2 ≤ 6^2
to find out 
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a² 
so p = k × a²
so that
x = a cosθ 
y = a sinθ 
dA = adθda
so 
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to  for θ
 for θ
I(x) =  y²p dA
 y²p dA
I(x) =  (a sinθ)²(k × a²) adθda
 (a sinθ)²(k × a²) adθda
I(x) = k   da ×
  da ×   (sin²θ)dθ
  (sin²θ)dθ
I(x) = k   da ×
  da ×   (1-cos2θ)/2 dθ
  (1-cos2θ)/2 dθ
I(x)  = k  ×
 ×   
 
I(x)  = k ×  × (
 × (   
 
I(x)  = k ×   ×
 ×    
 
I(x)  = 1444×k × .....................1
     .....................1
and we can say I(x) = I(y)   by the symmetry rule
and here I(o) will be  I(x) + I(y) i.e
I(o) = 2 × 1444×k × 
 
I(o) = 3888×k × ......................2
   ......................2
 
        
             
        
        
        
energy never disappears, for example, if you give some kinetic energy to a ball and it stops few seconds later, friction steals this energy to ground which ball was going on. "Law of Conservation of Energy" tell us that energy can't disappear
 
        
             
        
        
        
Answer:
space , small amount of gravity is found in the space ,infact we can say that there is no gravity in the space
 
        
                    
             
        
        
        
Answer:
The correct answer is 24.
Explanation:
 
        
                    
             
        
        
        
Answer:
The first part of the question is asking about BUOYANT FORCE or UPTHRUST.
Upthrust =TRUE WEIGHT-APPARENT WEIGHT
TRUE WEIGHT=mg
TRUE weight=50kg×10m/s²
=500N
upthrust=500N-380N
FB=120N
volume of the rock=mass/density.
since the granite is completely submerged, the volume of the displaced liquid will be equal to the volume of the body.
upthrust=Vdg
120N=V×1000kg/m³×10m/s²
120N=V×10000kg/m²s²
120/10000=V
v=0.012m³
please mark brainliest, hope it helped