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IgorC [24]
3 years ago
15

Simplify the expression and rewrite in rational exponent form.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

4 x^{\frac{11}{10}} \cdot y^{\frac{17}{3}}

Step-by-step explanation:

The given expression: 4 \sqrt[5]{x^{3}} \cdot y^{4} \cdot \sqrt{x} \cdot \sqrt[3]{y^{5}}

Step 1: Change radical to fractional exponent.

Formula for fractional exponent: \sqrt[n]{a}=a^{\frac{1}{n}}

The power to which the base is raised becomes the numerator and the root becomes the denominator.

\Rightarrow 4 x^{\frac{3}{5}} \cdot y^{4} \cdot x^{\frac{1}{2}} \cdot y^{\frac{5}{3}}  

Step 2: Apply law of exponent for a product a^{m} \times a^{n}=a^{m+n}  

Multiply powers with same base.

\Rightarrow 4 x^{\frac{3}{5}+\frac{1}{2}} \cdot y^{4+\frac{5}{8}}  

Take LCM for the fractions in the power.

\Rightarrow 4 x^{\frac{6}{10}+\frac{5}{10}} \cdot y^{\frac{12}{3}+\frac{5}{3}}  

\Rightarrow 4 x^{\frac{11}{10}} \cdot y^{\frac{17}{3}}

Hence the simplified form of 4 \sqrt[5]{x^{3}} \cdot y^{4} \cdot \sqrt{x} \cdot \sqrt[3]{y^{5}} \text { is } 4 x^{\frac{11}{10}} \cdot y^{\frac{17}{3}}.

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emmasim [6.3K]

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7 0
3 years ago
Hey You <br> YES YOU CAN ANSWER THIS PLEASE<br> solve for T: 4 j= -9T
OLEGan [10]
-9T means -9 x T
So if T is equivalent to 4,
you should do:
-9 x 4 = -36
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8 0
3 years ago
Asa <br> Sss<br> Sss<br> Sas <br> Aas <br> Hl <br> Not congruent
ELEN [110]

Answer:

HL is the correct answer of this question

4 0
3 years ago
Really do need help on this
melamori03 [73]
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7 0
3 years ago
Can someone please explain how to get the answer I've watched multiple videos on implicit derivatives and I still cant figure it
Arisa [49]

We're given the implicit equation

x² + 2x + y² - 4y = 12

where "implicit" means that one of the variables is considered a function of the other. In this case, the variable y = y(x) depends on the value of the variable x - in other words, the possible values of y are implied by the value of x. We then say that this equation defines y as an implicit function of x.

We're also given the implicit derivative,

dy/dx = (-2x - 2)/(2y - 4)

which tells us the rate of change y as a function of both x and y. The value of dy/dx corresponds to the slope of the tangent line to the curve defined by the implicit equation above at some point (x, y).

The tangent line is horizontal when its slope is zero. This happens when

(-2x - 2)/(2y - 4) = 0

If y ≠ 2, then we can eliminate the denominator and we're left with

-2x - 2 = 0

Solve for x :

-2x = 2

x = -1

This tells us that the points on the curve with x-coordinate -1 have a tangent line to the curve that is horizontal.

The tangent line is vertical when its slope is undefined/infinite, or equivalently when the denominator of dy/dx is zero:

2y - 4 = 0

Solve for y :

2y = 4

y = 2

So any point on the curve with y-coordinate 2 will have a tangent line there that is vertical.

By completing the square in the implicit equation, we can easily identify where these points are located.

x² + 2x + y² - 4y = 12

x² + 2x + 1 + y² - 4y + 4 = 17

(x + 1)² + (y - 2)² = 17

This equation defines a circle centered at (-1, 2) with radius √17. When x = -1, we have

(y - 2)² = 17   ⇒   y = 2 ± √17

and when y = 2, we have

(x + 1)² = 17   ⇒   x = -1 ± √17

See the attached plot to see the circle and the tangents at these points.

7 0
2 years ago
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