1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
worty [1.4K]
3 years ago
8

Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i

Mathematics
1 answer:
ELEN [110]3 years ago
8 0
<h2>Answer:</h2>

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

<h2>Step-by-step explanation:</h2>

Given:

<em>First lamp rating</em>

Power (P) = 100W

Voltage (V) = 110V

<em>Second lamp rating</em>

Power (P) = 100W

Voltage (V) = 220V

<em>Source</em>

Voltage = 220V

i. <u>Get the resistance of each lamp</u>.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = \frac{V^2}{R}

<em>Make R subject of the formula</em>

⇒ R = \frac{V^2}{P}             ------------------(i)

<em />

<em>For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)</em>

R₁ = \frac{110^2}{100}

R₁ = 121Ω

<em />

<em>For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)</em>

R₂ = \frac{220^2}{100}

R₂ = 484Ω

<em />

<em />

ii.<u> Get the equivalent resistance of the resistances of the lamps.</u>

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R  = 121 + 484

R = 605Ω

iii. <u>Get the current flowing through each of the lamps. </u>

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = \frac{V}{R}

I = \frac{220}{605}

I = 0.36A

iv. <u>Get the power consumed by each lamp.</u>

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

<em>For the first lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

<em>For the second lamp, power consumed is given by;</em>

P = I²R           [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

You might be interested in
Stacy is saving $5 each week to buy a new bike. She already has 15 dollars saved in her bank account. SHe needs to save at least
kotykmax [81]

She nee to save $60 more so she can buy a new bike

3 0
3 years ago
Law of cosines.Anyone good in Trigonometry?​
marin [14]

Answer:

c=11.8\ units

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

c^2=a^2+b^2-2(a)(b)cos(C)

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

a=3\ units\\b=10\ units

C=120^o

substitute the given values

c^2=3^2+10^2-2(3)(10)cos(120^o)

c^2=109-(60)cos(120^o)

c^2=109-(60)(-0.5))

c^2=109+30

c^2=139

c=11.8\ units

3 0
3 years ago
If 11 - 3x = x, then 20x=
dimaraw [331]

Answer:

20x = 55

Step-by-step explanation:

First you have to add 3x to both sides of 11-3x=x

11-3x=x\\+3x=+3x\\11=4x

Now that you have 11 = 4x you divide 4 on both sides \frac{11}{4} =\frac{4x}{4}

11/4 = x

But you can't divide 11 by 4 unless you are looking for the decimal form of 11/4 which is 2.75

so now we take 11/4 or 2.75 depending on if you need your answer in fraction or as a decimal and replace that with x  however both will equal the number 55

20(\frac{11}{4})=55\\20(2.75)=55

4 0
2 years ago
In ANOP, the measure of P=90°, PN = 95 feet, and OP = 31 feet. Find the measure
sweet-ann [11.9K]

Answer: 72

Step-by-step explanation:

6 0
2 years ago
The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (
sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

\dfrac{dr}{dt} = 1\text{ meter per hour}                

The height is decreasing at a rate 4 meter per hour  

\dfrac{dh}{dt} = -4\text{ meter per hour}

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

\pi r^2 h

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}

Putting all the values we get,

\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

3 0
3 years ago
Other questions:
  • Consider the function m(t) = -28/5t
    10·1 answer
  • A construction crew built 1/2 miles of road in 1/6 days. What is the unit rate in miles per day? Write your answer in simplest f
    14·1 answer
  • Are you good at math then here
    7·1 answer
  • Which values are possible rational roots of 12x^3 + 14x^2 - x + 18 = 0 according to the rational root theorem?
    15·1 answer
  • Find the second derivative y= x^2lnx
    14·1 answer
  • What is the value of the expression below?<br> (5^1/2)^2
    7·1 answer
  • find the area of a circle with a radius of two either enter an exact answer in terms of pi or use 3.14 for pi and enter your ans
    14·2 answers
  • If a truck travels for 3 hours, how many miles will it travel? __ miles
    15·2 answers
  • One morning, the temperature in Urbana, Illinois, was 15° Fahrenheit. By evening, the temperature had dropped 25° Fahrenheit. Wh
    13·1 answer
  • 10 added to the product of g and y?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!